The Hall voltage across a 0.800-mm-thick conductor in a 1.30 T magnetic field is 3.2 uV when the current is 12.0 A.(adsbygoogle = window.adsbygoogle || []).push({});

What is the charge carrier denisty in the conductor (in m^{-3}).

I was using the equation V_{h}=IB/ned

where V_{h}is the Hall voltage

I is the current

B is the magnetic field

n is the charge-carrier density

e is the charge of an electron

and d is the thickness

I rearranged to get n=IB/V_{h}ed

and evaluated to get 3.806*10^{25}m^{-3}

But this came up wrong on the assignment and it looks like an unreasonable answer. I think I need additional values but basically this entire question is really confusing me.

Thanks for the help!

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# Homework Help: What is the charge carrier density in the conductor

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