What is the coefficient of static friction for a penny on a rotating wheel?

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Homework Help Overview

The problem involves determining the coefficient of static friction for a penny placed on a rotating wheel. The scenario describes a penny sliding off the wheel when the rotational speed reaches a specific value, and participants are exploring the relationship between centripetal force, acceleration, and friction.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculations related to centripetal acceleration and the need to relate it to the coefficient of static friction. There is a focus on identifying the forces involved and the correct application of equations.

Discussion Status

Some participants have provided guidance on the distinction between acceleration and the coefficient of static friction, noting the importance of including gravitational acceleration in the calculations. There is an ongoing exploration of the necessary steps to arrive at the correct answer.

Contextual Notes

The original poster's calculations appear to have omitted the gravitational force component, which is crucial for determining the coefficient of static friction. The problem is framed within the context of a homework assignment, which may impose specific constraints on the approach taken.

d.tran103
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Can someone look at this and tell me what I'm doing wrong? Thanks!

Homework Statement


You place a penny on a level rotating wheel at a point 5.00 cm from the center of rotation. You increase the speed of rotation gradually, and once you reach a rotational speed of 0.825 revolutions each second, the penny slides off the wheel. What is the coefficient of static friction

a) 0.718

b) 0.409

c) 0.253

d) 0.137

Homework Equations


Fc = mv^2/r = mac
v=wr

The Attempt at a Solution


Fc = mv^2/r = mac

mv^2/r = mac turns to v^2/r = ac. I converted 0.825 rev/s to rad/s by multiplying by 2pi/1rev to get 5.18 rad/s. I plugged w into v=wr, v=(5.18 rad/s)(.05m) to get v=.259 m/s. I plugged v into v^2/r = ac, .259^2/.05 and got 1.34. However, 1.34 isn't an answer. Can someone tell me what I'm doing wrong?
 
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You found the acceleration. The question isn't asking for the acceleration. It's asking for a coefficient of static friction. That's the ratio between the normal force and the centripetal force. There should be a g=9.8m/sec^2 in there somewhere.
 
You solved for the centripetal acceleration. Now you need to find and identify the centripetal force.
 
Thanks, I was missing 1/9.8!
 

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