What is the Contour Integral of Log(z) on a Specific Contour?

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The discussion focuses on finding the contour integral of Log(z) along the specified contour defined by x^2 + 4y^2 = 4 in the first quadrant. The parametrization of the contour is given as z(t) = 2cos(t) + isin(t) for t ranging from 0 to π/2. The integral is expressed as ∫Log(z(t))z'(t)dt, but there is confusion regarding the calculation of Log(z(t)). The participant questions the use of the Fundamental Theorem of Calculus, wondering why it cannot be applied given the known starting and ending points of integration. The discussion highlights challenges in determining the logarithmic function and its antiderivatives in this context.
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Homework Statement


Find the contour integral of Log(z). The contour is defined as: x^2 + 4y^2 = 4, x>= 0, y>=0

Homework Equations




The Attempt at a Solution


parametrize the contour as z(t) = 2cos(t) + isin(t)
0 <= t <= pi/2
The contour integral = ∫Log(z(t))z'(t)dt
I am having trouble finding Log(z(t)).
Log(z(t)) = ln|z(t)| + iArg(z(t))

Would ln|z(t)| = ln|sqrt(1 + 3cos(t)^2)| and Arg(z(t)) = t?
 
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What's wrong with antiderivatives? I mean why not use the Fundamental Theorem of Calculus for this? You know the starting point of integration and the ending point so poke-a-poke right?
 
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