What Is the Correct Calculation of Energy Density in a Charged Capacitor?

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Homework Help Overview

The problem involves calculating the energy density of a parallel-plate capacitor, given its capacitance, energy stored, and plate separation. The participants are exploring the relationships between capacitance, energy, and volume in the context of electrostatics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the formula for capacitance and its relation to area and separation distance. There are questions about the correct interpretation of capacitance units and how to calculate the volume of the capacitor. Some participants express uncertainty about whether the volume is necessary for the calculation of energy density.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the steps needed to find the area of the capacitor plates and how it relates to the overall calculation. Guidance has been offered regarding the need for volume in the energy density calculation, and there is active exploration of the formulas involved.

Contextual Notes

There is some confusion regarding the units of capacitance and the necessary parameters to compute the volume. The participants are working within the constraints of the problem statement and the equations provided.

baker265
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Homework Statement



A parallel-plate capacitor with C = 16 mu or micro FF is charged so as to contain 1.7 J of energy. If the capacitor has a vacuum between plates that are spaced by 0.35 mm, what is the energy density (the energy per unit volume)?

I am a little lost of this problem and have no idea if I'm doing it correctly. Am I ?

Homework Equations


v = A*d
E,density=U/v


The Attempt at a Solution


v=16e-3/.35e-3=45.71
E=1.7/45.71=.0371 J/m^3
 
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baker265 said:

Homework Statement



A parallel-plate capacitor with C = 16 mu or micro FF is charged so as to contain 1.7 J of energy. If the capacitor has a vacuum between plates that are spaced by 0.35 mm, what is the energy density (the energy per unit volume)?

I am a little lost of this problem and have no idea if I'm doing it correctly. Am I ?

Homework Equations


v = A*d
E,density=U/v


The Attempt at a Solution


v=16e-3/.35e-3=45.71 ?
E=1.7/45.71=.0371 J/m^3

Is the capacitance 16 μF (microfarad)?

How do you calculate the volume?

ehild
 
Yes, I believe that is (microfarad); it doesn't say specifically.
I was very unsure on that step and wasn't quite sure how to compute the volume. Do I even to find the volume?
 
As yo have written, energy density is energy divided by volume. So you need it.

ehild
 
Okay so how do I find the area in order to find volume.
 
What is the formula for the capacitance? ehild
 
C=(k* epsilon_0*A)/d
 
The volume between the plates is given by Ad where 'A' is area of the plates and 'd' is separation between them . 'd' is given whereas 'A' is unknown .

Using C= ε0A/d ,find the value of A.

Now,energy density = Energy stored/volume .
 

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