What is the Correct Concept for Solving the Stacked Blocks Problem?

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The discussion centers on the correct approach to solving the stacked blocks problem involving friction and acceleration. It emphasizes that when block X does not slip on block Y, both blocks must move together with the same acceleration. The applied force F affects block Y, while friction between the blocks influences their motion. The net horizontal force on block Y is the applied force minus the frictional force, which is crucial for determining acceleration. A free body diagram for each block is recommended for clarity in understanding the forces at play.
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Homework Statement


177cf5c7d0.png


Homework Equations


F= ma[/B]

The Attempt at a Solution


X does not slip. so friction exists. Friction should be equal to the force F applied so that according to Newton's 3rd law, the friction and F cancel out and X remains on Y.
Is this the right concept?
 
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Arun Raja said:

Homework Statement


177cf5c7d0.png


Homework Equations


F= ma[/B]

The Attempt at a Solution


X does not slip. so friction exists. Friction should be equal to the force F applied so that according to Newton's 3rd law, the friction and F cancel out and X remains on Y.
Is this the right concept?
No. F is applied on Y. The friction between X and Y acts also on X. So the net horizontal force exerted on Y is F-friction. If F and the friction cancel out Y does not accelerate. As X moves together with Y the whole system stays in rest or moves without acceleration. But the problem stated that it accelerates.
X does not slip on Y means that they move together, with the same acceleration.
ehild
 
That would be fine if the boxes moved at a constant speed ... but they don't.
Instead, draw a free body diagram for each block.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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