SUMMARY
The discussion centers on determining the correct formula of a metal oxide based on the provided data: "0.1 mol of metal X (Ar = 27) was burned in oxygen to give an oxide with mass of 5.1g." The calculations reveal that the mass of metal X is 2.7g, leading to 2.4g of oxygen, which converts to 0.15 moles. This results in a metal to oxygen ratio of 2:3, indicating the formula X2O3, which corresponds to Aluminium Oxide (Al2O3). The conversation highlights the confusion stemming from the question's wording and the significance of the atomic mass provided.
PREREQUISITES
- Understanding of stoichiometry and mole calculations
- Familiarity with atomic mass and molar mass concepts
- Knowledge of chemical formulas and balancing equations
- Basic principles of combustion reactions
NEXT STEPS
- Study stoichiometric calculations in chemical reactions
- Learn about the properties and applications of Aluminium Oxide (Al2O3)
- Explore the concept of atomic mass and its implications in chemical formulas
- Review balancing chemical equations and their significance in reaction stoichiometry
USEFUL FOR
Chemistry students, educators, and professionals involved in chemical analysis, particularly those focusing on stoichiometry and metal oxide formulations.