- #1

superslow991

- 78

- 1

## Homework Statement

An ac series circuit consists of a voltage source of frequency f = 60 Hz and voltage amplitude V, a resistor of resistance R = 163 ohms and a capacitor of capacitance C = 6.2x10^-6 F. What must the source voltage amplitude V be for the average electrical power consumed in the resistor to be 529 watts? There is no inductance in the circuit.

## Homework Equations

*X*C = 1 / (2 × π ×

*f*×

*C*)

Z = √(R2 + X2)

P=V^2/R

## The Attempt at a Solution

So first i calculated the reactance and got 1/(2*π*60*6.2*10^-6)= 428.05

next impedance-√(163^2 + 428.05^2)= 458.0

last i used the power equation - 529=v^2/458.0 and solved for v and got 492.2 V

My only question is I've checked different answers online and saw some as V = 1165 or 1166

just wondering if i did the math right on this question. Any help is appreciated.