Calculating Currents & Voltages of an RLC Circuit

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SUMMARY

The discussion focuses on calculating the currents and voltages in a series RLC circuit consisting of a 15Ω resistor, a 200μF capacitor, and a 12mH inductor. The current through the circuit is established as I=1.75A⋅cos(250πt). The voltage across the power source is calculated to be V=26.79V⋅cos(250πt+0.201), while the voltages across the resistor, capacitor, and inductor are V=26.25V⋅cos(250πt), V=11.14V⋅cos(250πt-(π/2)), and V=16.49V⋅cos(250πt+(π/2)), respectively. These calculations confirm the relationships between current and voltage in the RLC circuit.

PREREQUISITES
  • Understanding of RLC circuit components (resistor, inductor, capacitor)
  • Familiarity with phasor analysis in AC circuits
  • Knowledge of impedance (Z) and phase angle (φ) calculations
  • Proficiency in using trigonometric identities for AC voltage and current
NEXT STEPS
  • Study the concept of impedance in RLC circuits
  • Learn how to derive the phase angle (φ) in AC circuits
  • Explore the use of phasors for analyzing AC circuit behavior
  • Investigate the effects of varying frequency on RLC circuit performance
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing or designing RLC circuits will benefit from this discussion.

Chemmjr18
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Homework Statement


An RLC circuit contains the following components in series: a 15Ω resistor, a 200μF capacitor, and a 12mH inductor. What are the currents and voltages through each component?

It's known that the current through the resistor is 1.75A⋅cos(250πt)

Homework Equations


χL=ω*L
χC=1/(ωC)
Z=√(R2+(χLC)2)
φ=tan-1((χLC)/R)
Vi=Ii*Z

The Attempt at a Solution


This what I got when solving:

The current through each component is the same. I=1.75A⋅cos(250πt)

The voltage across the power source is V=26.79V⋅cos(250πt+0.201)

The voltage across the resistor is V=26.25V⋅cos(250πt)

The voltage across the capacitor is V=11.14⋅cos(250πt-(π/2))

The voltage across the inductor is V=16.49⋅cos(250πt+(π/2))
 
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I got the same thing.
 
Last edited:
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scottdave said:
I gotthe same thing.
Victory! Thanks!
 
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