What Is the Correct Velocity of a Bungee Jumper as the Cord Begins to Stretch?

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SUMMARY

The correct velocity of a bungee jumper, Lola, as the cord begins to stretch can be calculated using the equation V=√(k/m)(A)^2. With a bungee cord spring constant of k=700 N/m, a mass of 45 kg, and an unstretched cord length of 50 m, the calculated velocity is 197.20 m/s. However, this value is misleading as it does not account for the initial free fall before the cord stretches. The jumper's velocity at the moment the cord begins to stretch is simply the result of gravitational acceleration, not the spring equation.

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Lola goes bungee jumping. She leaps from a bridge that is 100 m above a river. Her bungee cord has an unstretched length of 50 m and a spring constant k=700N/m. lola has a mass of 45 kg. How fast is she falling when she just starts to stretch the cord? How long does it take for Lola to reach this point.

I used the equation V=√(k/m)(A)^2 and I got

V=√(700N/m/45kg)(50m)^2)=197.20m/s

I was wondering If I used the right equation b/c the answer seems awfully high.

The second part of the question i don't know which equation to use.
Thanks
 
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Just ignore the spring, because it is not being stretched yet. She's just plain old falling.
 

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