Mitchtwitchita
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can anybody tell me what the critical point of xe^x is? When I try putting it into my calculator, it just shows a line staring at zero with an asymptote at x=1.
The discussion revolves around finding the critical point of the function \( xe^x \). Participants explore the definition of critical points, the process of differentiation, and the implications of using calculators for such problems.
Participants do not reach consensus on the interpretation of the function's behavior at \( x=1 \) and the use of calculators. There are conflicting views on the clarity of the critical point definition and the implications of the derivative's value.
There are unresolved questions regarding the assumptions made about the function's behavior and the potential misinterpretation of calculator outputs. The discussion reflects varying levels of understanding of critical points and differentiation.
Then you don't got it. If "when x= 1, the answer is -1" is in response to my question "What is the value of y= xex when x= 1?" (my point being that if it has a value, x= 1 cannot be an asyptote), then when x= 1, y= xex= 1(e1)= 1. I can't imagine how you would get a negative number for that. And you have already been told that the critical point is NOT at x= 1.Mitchtwitchita said:Thanks for your help guys. I think I got it now. When x=1, the answer is -1. This is the critical point for the function. I don't what the deal was with my calculator. It could have been the scale. Anyhoo, thanks again.