What is the de Broglie wavelength of a falling neutron in a vacuum?

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SUMMARY

The de Broglie wavelength of a neutron that has fallen 0.60 meters in a vacuum is calculated using the formula λ=h/mv. The velocity of the neutron, determined through the equation v²=2ax with an acceleration of 9.81 m/s², is found to be 3.43 m/s. Substituting the correct values, where the mass m is 1.67 x 10-27 kg and Planck's constant h is 6.67 x 10-34 J·s, results in a de Broglie wavelength of approximately 5.87 x 10-8 meters. Accurate unit measurement and the correct application of physics principles are crucial for this calculation.

PREREQUISITES
  • Understanding of classical mechanics, specifically free fall and gravitational acceleration.
  • Familiarity with the de Broglie wavelength formula λ=h/mv.
  • Knowledge of kinetic energy and its relationship to potential energy.
  • Ability to perform unit conversions and dimensional analysis.
NEXT STEPS
  • Study the derivation and applications of the de Broglie wavelength in quantum mechanics.
  • Learn about gravitational potential energy and its conversion to kinetic energy.
  • Explore the implications of wave-particle duality in quantum physics.
  • Investigate the significance of Planck's constant in various physical equations.
USEFUL FOR

Physics students, educators, and anyone interested in quantum mechanics and the behavior of particles in a gravitational field.

DRC12
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Homework Statement


What is the de Broglie wavelength of a neutron that has fallen 0.60 in a vacuum chamber, starting from rest?

Homework Equations


Not entirely sure
λ=h/mv

The Attempt at a Solution


I can't figure out what the velocity is, I think it would have to do with the change in kinetic energy but I can't figure out what that would be
 
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DRC12 said:

Homework Statement


What is the de Broglie wavelength of a neutron that has fallen 0.60 in a vacuum chamber, starting from rest?

Homework Equations


Not entirely sure
λ=h/mv

The Attempt at a Solution


I can't figure out what the velocity is, I think it would have to do with the change in kinetic energy but I can't figure out what that would be
Is the distance 0.6 m, cm, mm? Units, as well as magnitude, are rather important to a physics or engineering, or other quantitative problem.

If the neutron is in freefall - what is the acceleration? Knowing the acceleration and distance, one can determine the velocity at that distance.
 
The other way to look at it, instead of calculating accelerations and integrating back to get velocity, is to look at the Energy. The change in energy is just mg*(change in height) and this goes into the kinetic energy i.e. 1/2 mv^2.
 
Astronuc said:
Is the distance 0.6 m, cm, mm?
meters

I tried finding the velocity using v2=2ax
and found v to be 3.43m/s
then I plugged that into λ=h/mv
where m=1.67*10-27kg and h=6.67*10-34
and found λ=5.87*10-8
 
wait for some reason I was using h=3.36E-34 instead of 6.67E-34 I don't even know where that number came from
 

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