What is the Density of a Mixture of Two Liquids in a 1:3 Ratio?

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The density of a mixture of two liquids in a 1:3 mass ratio, with densities of 1.25 gm/cc and 0.6 gm/cc, is calculated to be approximately 0.69 gm/cc. The total mass of the mixture is 100 gm, leading to individual masses of 25 gm and 75 gm for the two liquids. The volumes of the liquids are derived from their respective masses and densities, resulting in a total volume of 145 cm³. The final density is confirmed through the formula D = mass/volume.

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Homework Statement


In a mixture of 100 gm , 2 liquids are mixed in ratio 1:3 of their masses . If densities of liquids are 1.25gm/cc and 0.6gm/cc , find the density of mixture.


Homework Equations


D = mass/Volume


The Attempt at a Solution


mass = 100g
let m1 = x , m2 = 3x
d1 = 1.25 gm/cc , d2 = 0.6gm/cc
mass = m1+m2
100= 4x
100/4 = x
m1 = 25, m2 = 75
V1= 25/125*100 = 20cm3
V2 = 75/6*10 = 125cm3
d = mass/volume
= 100/145 = 20/29 = 0.6gm/cc

is that ^^ correct?
 
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d = mass/volume
= 100/145 = 20/29 = 0.6gm/cc


Correct. But wright as 0.69 gm/cc
 
ok , thank you :)
 

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