What is the Derivative of (1+tanx)?

[fitz_calc]

real quick review needed, I'm working through the quotient rule on a problem and need the first derivative of:

(1+tanx)

is it simply equal to:

(0 + sec^2x * 1)
(sec^2 x)

??

 

[rocomath]

yes that's correct

1 = 0, \tan{x}=\sec^2{x}

 

[CompuChip]

1 = 0

Geez, that's a nice identity.
I wish I could use that on my exam, it would make life a lot easier

 

[rocomath]

Geez, that's a nice identity.
I wish I could use that on my exam, it would make life a lot easier

lol, you know what i meant ;)

 

[CompuChip]

Yeah, I know you meant

1' = 0, \tan(x)' = \sec^2(x)
where ' = \frac{\rm d}{{\rm d}x}.