What is the derivative of cosh inverse x?

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SUMMARY

The derivative of the inverse hyperbolic cosine function, denoted as cosh-1x, is confirmed to be \(\frac{1}{\sqrt{x^2 - 1}}\). The inverse function is expressed as \(ln(x + \sqrt{x^2 - 1})\). To derive this, one can set \(y = arccoshx\), apply the definition \(coshy = x\), and differentiate using the identity \(cosh^2(y) - sinh^2(y) = 1\). This method validates the derivative effectively.

PREREQUISITES
  • Understanding of hyperbolic functions, specifically cosh and sinh.
  • Familiarity with inverse functions and their derivatives.
  • Knowledge of logarithmic functions and their properties.
  • Basic calculus concepts, including differentiation techniques.
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  • Study the properties and graphs of hyperbolic functions.
  • Learn about the derivation of inverse trigonometric functions.
  • Explore the applications of hyperbolic functions in calculus.
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Students studying calculus, mathematics educators, and anyone interested in advanced mathematical concepts related to hyperbolic functions and their derivatives.

JFonseka
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Homework Statement



Derive cosh^{-1}x

Homework Equations



None I know of.

The Attempt at a Solution



Well I vaguely remember that the inverse of this was something like

ln(x + \sqrt{x^2 - 1})

If I derive this, I will get \frac{1}{\sqrt{x^2 - 1}}

Is that correct? Am I wrong to assume the equation for the inverse of cosh? Or do I need to prove that as well
 
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actually...\frac{d}{dx}arccoshx=\frac{1}{\sqrt{x^2-1}}

prove it by just letting y=arccoshx and then putting coshy=x and findind dy/dx
and use the identity cosh^2(x)-sinh^2(x)=1
 

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