- #1

barryj

- 856

- 51

- Homework Statement
- I need to calculate the expression for the derivative of the inverse tan and sin. I have written my solution of the inverse tan on the attachment but I have questions. Also, using the same method, the calculation of the derivative of the inverse sin does not work.

- Relevant Equations
- y = tan^-1(x) find dy/dx and y = sin^-1(x) find dy/dx

I calculated an expression for the derivative of the inverse tan but I did not use the identity as suggested. Why did I need to use this identity. Did I do the problem correctly? I got the correct answer.

I tried to do the derivative of the inverse sin the same way. I used the same figure 1 on the diagram that I used for the tan problem. However, my answer, sqrt(x^2 + 1) is not correct, The correct answer, according to the book is 1/sqrt(1-x^2).

I cannot see the error.

I tried to do the derivative of the inverse sin the same way. I used the same figure 1 on the diagram that I used for the tan problem. However, my answer, sqrt(x^2 + 1) is not correct, The correct answer, according to the book is 1/sqrt(1-x^2).

I cannot see the error.