Purpose of the derivative of the inverse function

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Homework Help Overview

The discussion revolves around the derivative of the inverse function, particularly in the context of calculus and its applications in physics. Participants explore its relevance and seek examples that illustrate its practical use beyond theoretical exercises.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to understand the practical applications of the derivative of the inverse function, questioning whether it is merely an academic exercise. Some participants provide a scenario involving engine speed control to illustrate its application. Others inquire about additional examples where this derivative is useful.

Discussion Status

The discussion is ongoing, with participants sharing insights and examples related to the derivative of the inverse function. While some guidance has been offered, particularly regarding its application in a physical context, there is no explicit consensus on the breadth of its usefulness or additional examples.

Contextual Notes

Participants are navigating the balance between theoretical understanding and practical application, with some expressing uncertainty about the relevance of the derivative of the inverse function in real-world scenarios. There is also mention of the linear approximation aspect of the derivative in specific settings.

barryj
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Homework Statement


In calculus, I learn that the derivative of the inverse function is

g'(x) = 1/ f'(g(x))

Homework Equations


So..

The Attempt at a Solution



Can someone give me an example of where I need to know this, or is this just a math exercise. Is there a relatively simple physics example?
 
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Sure. Suppose you are controlling an engine speed with a dial. If you want to increase the speed by 3 rpm, how much should you increase the dial setting?

PS. Keep in mind that this gives a linear estimate at that setting. It maybe very different at another setting.
 
Don't go away for long. I will be back in4 hours.
 
This property of the derivative of the inverse function is just a simple observation of what a slope is when looked at from another direction. As such, it has applications everywhere.
 
Last edited:
What is the derivative of ##\arccos x##? Good luck with using the definition.
 
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OK, finding the derivative of arccos(x)
given... f(x) = cos(X) and g(x) = cos^-1(x)

then g'(x) = 1/f'(g(x))

g'(x) = 1/-sin(g(x))

g'(x) = 1/-sin(cos^-1(x))

then after some trig substitutions we get this is equal to ##-1/\sqrt(1-u^2)##or something like this.
 
barryj said:
OK, finding the derivative of arccos(x)
given... f(x) = cos(X) and g(x) = cos^-1(x)

then g'(x) = 1/f'(g(x))

g'(x) = 1/-sin(g(x))

g'(x) = 1/-sin(cos^-1(x))

then after some trig substitutions we get this is equal to ##-1/\sqrt(1-u^2)##or something like this.

This is one of the numerous examples where it is useful.
 
Could someone give me a few more examples where finding the derivative of the inverse function is useful.
 

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