(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A laboratory lead consists of 16 strands of fine copper wire twisted together. Each strand is 30 cm long with a diameter of 0.15 mm. Calculate the potential difference across the lead when it is carrying a current of 2.0 A.

(The resistivity of copper = 1.7 × 10^-8 Ohm*m)

2. Relevant equations

What I would do is R = pl/A and then multiply by 2

BUT I can't find R

3. The attempt at a solution

(the answer is. apparantly, 0.036 V but I cant see how)

I said R = [(1.7*10^-8)*16*0.3)/(pi*0.15/20000)^2)

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# Calculating the resistance from R = pl/A

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