What is the difference between ln 4 and log 4?

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The discussion clarifies the distinction between ln 4 and log 4, emphasizing that ln 4 represents the natural logarithm (logarithm base e) while log 4 can refer to logarithm base 10 or base e, depending on the context. The integral of (1/x) from 1 to 4 yields ln 4, confirming that ln 4 > log 4 when log refers to base 10. The notation used for logarithms is crucial in determining their equivalence, with ln(x) consistently defined as log_e(x).

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I am reviewing Calculus 1 integration learned long ago in the 1990s.

Integrate (1/x) dx from 1 to 4.

The textbook answer is ln 4.

However, many of my friends tell me that the answer can also be written as log 4.

But, ln 4 does NOT equal log 4.

In fact, ln 4 > log 4.

Who is right? Why?
 
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It depends on what shorthand notation one uses for $\log_e(x)$.
 
MarkFL said:
It depends on what shorthand notation one uses for $\log_e(x)$.

The integral of (1/x) is ln x.

From 1 to 4:

ln 4 - ln 1

ln 4 - 0

Answer: ln 4

However, my friend said the following:

log 4 - log 1

log 4 - 0

log 4

Who is right?
 
I'll expand a bit beyond MarkFL's comment. You problem is a matter of notation, not a conceptual one.

In many sources we have that [math]ln(x) = log_e(x)[/math]. Sometimes you will see [math]log_e(x) = log(x)[/math]. In fact some also say that [math]log_{10}(x) = log(x)[/math].

In your case we need the [math]ln(4) = log_e(x)[/math].

-Dan
 

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