What is the difference between ln 4 and log 4?

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Discussion Overview

The discussion centers on the difference between ln 4 and log 4, particularly in the context of integration and notation in mathematics. Participants explore the implications of different logarithmic notations and their equivalences in calculus.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant asserts that ln 4 does not equal log 4 and claims that ln 4 is greater than log 4, questioning the correctness of this view.
  • Another participant suggests that the difference depends on the shorthand notation used for logarithms, specifically noting that ln(x) is often defined as log_e(x).
  • A further contribution clarifies that the integral of (1/x) results in ln x, reinforcing that the answer from 1 to 4 is ln 4.
  • Some participants mention that log can refer to different bases, such as log_e(x) or log_{10}(x), indicating potential confusion in notation.

Areas of Agreement / Disagreement

Participants express differing views on whether ln 4 and log 4 are equivalent, with some arguing that it is a matter of notation rather than a conceptual difference. The discussion remains unresolved regarding the implications of these notations.

Contextual Notes

The discussion highlights limitations in notation clarity and the potential for confusion regarding the base of logarithms, which may affect interpretations of the claims made.

mathdad
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I am reviewing Calculus 1 integration learned long ago in the 1990s.

Integrate (1/x) dx from 1 to 4.

The textbook answer is ln 4.

However, many of my friends tell me that the answer can also be written as log 4.

But, ln 4 does NOT equal log 4.

In fact, ln 4 > log 4.

Who is right? Why?
 
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It depends on what shorthand notation one uses for $\log_e(x)$.
 
MarkFL said:
It depends on what shorthand notation one uses for $\log_e(x)$.

The integral of (1/x) is ln x.

From 1 to 4:

ln 4 - ln 1

ln 4 - 0

Answer: ln 4

However, my friend said the following:

log 4 - log 1

log 4 - 0

log 4

Who is right?
 
I'll expand a bit beyond MarkFL's comment. You problem is a matter of notation, not a conceptual one.

In many sources we have that [math]ln(x) = log_e(x)[/math]. Sometimes you will see [math]log_e(x) = log(x)[/math]. In fact some also say that [math]log_{10}(x) = log(x)[/math].

In your case we need the [math]ln(4) = log_e(x)[/math].

-Dan
 

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