What is the Direction of the Net Force on Earth?

Click For Summary
SUMMARY

The net force acting on Earth due to the gravitational attraction from the Moon and the Sun can be calculated using vector addition, specifically applying the Pythagorean theorem due to the right triangle formed by these celestial bodies. The magnitude of the net force is determined to be 3.52e22 N. To find the direction, one should utilize trigonometric functions such as tangent, sine, or cosine, based on the forces exerted by the Moon and the Sun. The angle can be calculated using the formula tan(angle) = opposite/adjacent, where the opposite leg represents the force from the Moon and the adjacent leg represents the force from the Sun.

PREREQUISITES
  • Understanding of gravitational forces and their calculations
  • Familiarity with trigonometric functions (sine, cosine, tangent)
  • Knowledge of vector addition in physics
  • Basic geometry, specifically right triangles
NEXT STEPS
  • Study gravitational force calculations between celestial bodies
  • Learn about vector addition and its applications in physics
  • Explore trigonometric functions in the context of physics problems
  • Investigate the concept of gravitational attraction in orbital mechanics
USEFUL FOR

Students and educators in physics, astrophysics enthusiasts, and anyone interested in understanding gravitational interactions between celestial bodies like the Earth, Moon, and Sun.

laxanimal
Messages
3
Reaction score
0
Hi all,

I've been working on this problem for a long while and just can't get the answer.

When the Earth, Moon, and Sun form a right triangle with the Earth located at the right angle, the Moon is approaching its third quarter. (The Earth is viewed here from above its north pole.) Find the magnitude and direction of the net force exerted on the Earth.

I found the magnitude to be 3.52e22 N but can't figure out what the direction is (been using tan**-1(force exerted by moon/force exerted by sun). Thanks in advance.
 
Last edited:
Physics news on Phys.org
Independently find the gravitational forces acting on the Earth due to the Sun and Moon. Then add the vectors together, which is in effect a pythagoreas in magnitude because of the right triangle geometry.
 
Thanks, I found the magnitude, but can't find the direction (the angle clockwise from the ray from Earth to sun) any suggestions?
 
This is a gravity question I assume, where the forces acting on the Earth are due to the forces of gravitational attraction between the Earth and the Sun/moon.

To find the resultant force acting on the Earth, you found the force caused by the moon, then force caused by the sun. These two forces are perpendicular to each other along the sides of right triangle, so you are able to calculate the resultant using the pythagorean theorem.
But there is another nifty thing you can employ since it is a right triangle, you know that the tangent of the angle is equal to the opposite "leg" of force / the adjacent "leg" of force.
Tan(angle) = opp / adj
or that,
Sin (angle) = opp / resultant, or
Cos(angle) = adj / resultant
Solving for the angle using anyone of these will work.


EDIT:
If you have been using,
tan^-1(force exerted by moon/force exerted by sun)
then your calling the force from the moon the opposite "leg" force, and the force from the sun, the adjacent "leg". The angle you will get would be the angle above the adjacent leg.
 
Last edited:
Thanks, I guess I don't know what angle I'm looking for. I found all of the angles in the triangle (90, 89.7, 0.328) and none of them work. Any help? Thanks.
 
One can determine the angle between the resultant force and either the line between the sun and earth, or the line between the moon and earth, the latter line being the tangent to the Earth's orbit based on the problem statement.

I have not evaluated the magnitudes of the forces, but the angles are probably about right. Draw a right triangle, and the resultant vector should be inside the triangle with it's base at the right angle vertex, and the point tilted slightly toward the sun.
 
what is force acting at right angle should be
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
21K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 21 ·
Replies
21
Views
1K
Replies
2
Views
25K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
16
Views
3K
Replies
1
Views
4K