What is the direction of velocity when a particle hits the surface of the sea?

[thereddevils]

Homework Statement

A particle is projected from the top of a vertical cliff with a speed of 40 m/s at an angle of elevation of 45 degrees towatds the sea . The particle hits the surface of the sea at a point whose horizontal distance from the cliff is 200 m . Find the direction of the velocity of the particle when it hits the surface of the sea . [Take g=10 m/s^2]

Homework Equations

The Attempt at a Solution

For horizontal motion ,

s=vt

200=40 cos 45 t

t=5 root (2)

For vertical motion ,

v=u+at

v=40 sin 45 -10(5 root 2)

=-(60)/(root 2)

This is the magnitude and i hv no idea how to find its direction

 

[Doc Al]

v=u+at

v=40 sin 45 -10(5 root 2)

This gives you the vertical component of the velocity, not the magnitude. What's the horizontal component? Use the components to find the angle.

 

[thereddevils]

This gives you the vertical component of the velocity, not the magnitude. What's the horizontal component? Use the components to find the angle.

argh , the answer is just right in front of me and i missed it . Thank you Sir .