What is the distance between the astronaut and the satellite after 1.0 min?

  • Thread starter Thread starter Patdon10
  • Start date Start date
  • Tags Tags
    Laws
Click For Summary
SUMMARY

The discussion centers on calculating the distance between an astronaut and a satellite after 1.0 minute, following an initial push. An astronaut with a mass of 80 kg exerts a force of 100 N on a 640 kg satellite for 0.50 seconds, resulting in different accelerations due to their masses. The astronaut's acceleration is calculated as 1.25 m/s², while the satellite's acceleration is 0.156 m/s². The correct distance apart after 1.0 minute is 42 meters, highlighting the importance of recognizing that the astronaut and satellite do not continue to accelerate after the initial push.

PREREQUISITES
  • Understanding of Newton's Third Law of Motion
  • Basic principles of kinematics, specifically distance and acceleration calculations
  • Familiarity with force equations (F = ma)
  • Knowledge of unit conversions and time intervals in physics
NEXT STEPS
  • Review Newton's Laws of Motion for deeper insights into force interactions
  • Study kinematic equations, particularly D = 1/2 a t², for distance calculations
  • Explore concepts of momentum conservation in space environments
  • Investigate the effects of initial conditions on motion in physics problems
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding motion dynamics in space environments.

Patdon10
Messages
85
Reaction score
0

Homework Statement


An 80 kg spacewalking astronaut pushes off a 640 kg satellite, exerting a 100 N force for the 0.50s it takes him to straighten him his arms. How far apart are the astronaut and the satellite after 1.0 min?

2. The attempt at a solution
F = Ma. Two different masses and two different accelerations. Because of Newton's 3rd law we know that the force the astronaut exerts on the satellite is equal to the force the satellite exerts on the astronaut.

F = (80)aastronaut
aastronaut = 1.25 m/s^2

F = 640kg(asatellite
asatellite = 640/100 = 0.156 m/s^2

Distance astronaut travels:
D = (1/2)(1.25)60^2 = 2250 m
D = (1/2)(.156)60^2 = 281.25 m

Total distance I got was ^ = 2531m, which is way wrong.
The correct answer is 42 m. Can anyone point me in the right direction?
 
Physics news on Phys.org
You applied the equation: D = 1/2 a t^2.

You put in a time of 60 seconds into this formula. After 1/2 sec of initial push, are they still accelerating?
 
Ugh...what a stupid mistake. Thanks.
 

Similar threads

Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 39 ·
2
Replies
39
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
6K