A particle P of mass 3 kg is projected up the line of greatest slope of a plane inclined at an angle of 50° to the horizontal. The coefficient of friction between P and the plane is 0.5. The intiial speed of P is 9 m/s. ii) Find the frictional force acting on P ii) What distance moved up the plane by P until its velocity becomes zero. 2. Relevant equations f = μ x N where N is the normal N = m x g x cos(50) 3. The attempt at a solution i) N = m x g x cos(50) = 19.28 N f = 0.5 x 19.28 = 9.64 N ii) Here I do not know what to do. I thought I could take -5 m/s^2 as a deceleration by using : f = μ x N m x a = 0.5 x m x g a = 5 m/s^2 and then using SUVAT equations but this is wrong since I do not get the answer shown in my book.. Please help! Thank you!