What is the distribution of forces on a swimming pool springboard?

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SUMMARY

The discussion centers on calculating the distribution of forces on a swimming pool springboard, specifically focusing on the reaction forces at points A and B. The springboard is 4 meters long and weighs 300N, with a boy weighing 400N standing at point C. The forces acting at points A and B are derived using equilibrium equations, leading to the conclusion that RA (reaction force at A) and RB (reaction force at B) must satisfy the conditions of static equilibrium. The calculations reveal inconsistencies in the initial assumptions regarding the torque and forces involved.

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Homework Statement



The diagram (not included) shows a straight, horizontal swimming bath spring board of length 4m and weight 300N. It is freely hinged at A and rests on a roller at B where AB=1.6m. A boy of weight 400N standard at end C.
a) show directions of forces acting on A and B
b) calculate magnitudes of forces at A and at B

Homework Equations



A______________B______________C
AB= 1.6m
BC= 2.4m
AC= 4m

The Attempt at a Solution


Weight of board put at centre point (0.4m from B and 2m from C)
RA assigned as reaction force at A
RB assigned as reaction force at B

RA = 700-RB

RA+RB = 700N
(300x2)+(4x400)=RA+(RBx1.6)
2200=RA+(RBx1.6)
2200=700-RB+(RBx1.6)
1500=0.6RB
2500=RB

This figure for RB simply cannot be right and therefore really isn't helping me!
 
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(300x2)+(4x400)=RA+(RBx1.6) ---> this is the equation for the torques with respect to A. Why did you include the force RA?

ehild
 
I assumed RA was required for the anticlockwise moment? is it not?
 
RA is force, not torque. What is the torque of RA with respect to A? ehild
 

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