Proving what the reaction force equals with moments in mechanics.

In summary, the problem involves a horizontal piece of wood held in equilibrium by two brackets, A and B, with a weight of 40N. The wood is 1.6m long, with A located 0.4m from C and B located 0.2m from D, resulting in a 1.0m distance between A and B. At rest, the reaction force at A is 24N and at B is 16N. When an object is placed on the wood at position x from C, the vertical reaction force at A can be calculated using the equation (24-W(x-1.4))N. To solve for the reaction force, the moment equation (x-1.4)
  • #1
xllx
33
0

Homework Statement


A horizontal piece of wood that has a weight 40N is held in equilibrium by two brackets, A and B. The wood is 1.6m long (CD). A is 0.4m from C and B is 0.2m from D. Meaning that there is 1.0m between A and B. At rest the reaction force at A is 24 N and at B 16N. When an object is put on the wood at xm from C, show that the vertical reaction force on the shelf at A is (24-W(x-1.4))N


Homework Equations


Moment=Force x Distance


The Attempt at a Solution


I understand that the W(x-1.4) is the moment of the object but I can't seem to get the 24.
If taking moments about B:
(x-1.4)W + (24 x 1) = 40 x 0.6
which isn't right

Any help at all would be greatly appreciated. many thanks.
 
Physics news on Phys.org
  • #2
xllx said:

Homework Statement


A horizontal piece of wood that has a weight 40N is held in equilibrium by two brackets, A and B. The wood is 1.6m long (CD). A is 0.4m from C and B is 0.2m from D. Meaning that there is 1.0m between A and B. At rest the reaction force at A is 24 N and at B 16N. When an object is put on the wood at xm from C, show that the vertical reaction force on the shelf at A is (24-W(x-1.4))N


Homework Equations


Moment=Force x Distance


The Attempt at a Solution


I understand that the W(x-1.4) is the moment of the object but I can't seem to get the 24.
If taking moments about B:
(x-1.4)W + (24 x 1) = 40 x 0.6
which isn't right

Any help at all would be greatly appreciated. many thanks.
The 24 N force at A is the reaction force before the object W is placed on the plank. It is given to you (or it could be calculated). By the superposition principle, the additional reaction at A as caused by W acting alone , is added to the existing 24N reaction at A.

EDIT:
If taking moments about B:
(x-1.4)W + (24 x 1) = 40 x 0.6
which isn't right
If you wish to start from scratch, it's
(1.4 -x)W -A(1) + 40(.6) =0
Solve for A. You have to watch your plus and minus signs (counterclockwise vs. clockwise moments) when summing moments about a point.
 
Last edited:

1. What is a reaction force in mechanics?

A reaction force is the force that is exerted by a body in response to an external force acting on it. In mechanics, it is often used to describe the force that is exerted by a surface or object in order to counteract the force applied to it.

2. How do you calculate the reaction force in mechanics?

The reaction force can be calculated by using the principle of moments in mechanics. This involves taking the sum of all the forces acting on a body and setting it equal to zero. By solving for the unknown force, we can determine the magnitude and direction of the reaction force.

3. What are moments in mechanics?

Moments in mechanics refer to the turning effect of a force around a pivot point. It is calculated by multiplying the magnitude of the force by the perpendicular distance from the pivot point to the line of action of the force.

4. Why is it important to determine the reaction force in mechanics?

The reaction force is important in mechanics because it allows us to analyze and understand the equilibrium of a system. By knowing the reaction force, we can determine if an object is stable or if it will move under the influence of external forces.

5. Can the reaction force ever be greater than the applied force in mechanics?

No, according to Newton's third law of motion, the reaction force is always equal in magnitude and opposite in direction to the applied force. Therefore, the reaction force can never be greater than the applied force in mechanics.

Similar threads

  • Introductory Physics Homework Help
Replies
7
Views
507
  • Introductory Physics Homework Help
Replies
3
Views
932
  • Introductory Physics Homework Help
Replies
2
Views
666
  • Introductory Physics Homework Help
Replies
3
Views
988
  • Introductory Physics Homework Help
Replies
15
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
4K
  • Introductory Physics Homework Help
2
Replies
43
Views
2K
  • Introductory Physics Homework Help
Replies
2
Views
5K
  • Introductory Physics Homework Help
Replies
7
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
824
Back
Top