1. The problem statement, all variables and given/known data A horizontal piece of wood that has a weight 40N is held in equilibrium by two brackets, A and B. The wood is 1.6m long (CD). A is 0.4m from C and B is 0.2m from D. Meaning that there is 1.0m between A and B. At rest the reaction force at A is 24 N and at B 16N. When an object is put on the wood at xm from C, show that the vertical reaction force on the shelf at A is (24-W(x-1.4))N 2. Relevant equations Moment=Force x Distance 3. The attempt at a solution I understand that the W(x-1.4) is the moment of the object but I cant seem to get the 24. If taking moments about B: (x-1.4)W + (24 x 1) = 40 x 0.6 which isn't right Any help at all would be greatly appreciated. many thanks.