What is the Domain of ln(x^2 + y^2)?

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SUMMARY

The domain of the function ln(x^2 + y^2) is defined as all points in the Cartesian plane except for the origin (0,0). The correct representation of this domain is (x^2 + y^2) > 0, which indicates that x and y cannot both be zero simultaneously. The initial assertion that x ≠ 0 and y ≠ 0 is misleading, as it implies that x and y can be zero at different times, which is not accurate. Therefore, the domain excludes only the point (0,0).

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Homework Statement



for the domain of ln (x^2 + y^2 ) , it it given in my notes that the ans is x ≠ 0 and y ≠ 0

IMO , it's wrong to give x ≠ 0 and y ≠ 0 , because the meaning of x ≠ 0 and y ≠ 0 is that x and y can't be 0 all the times so just leave the ans (x^2 + y^2 ) > 0 , will do ?

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when x = 0 , y not = 0 , z is defined , when y = 0 , z not = 0 , z is also undefined , So , x and y can be 0
 
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You are correct. The domain is the number plane excluding only the point (0,0) (the 'origin').
 
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The equation ##x^2 + y^2 = 0## can be thought of as a degenerate circle whose center is at (0, 0) and whose radius is 0. In other words, the point (0, 0). The graph of the solution set of the inequality ##x^2 + y^2 > 0## is all of the points in the plane outside that degenerate circle.
 
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Mark44 said:
The equation ##x^2 + y^2 = 0## can be thought of as a degenerate circle whose center is at (0, 0) and whose radius is 0. In other words, the point (0, 0). The graph of the solution set of the inequality ##x^2 + y^2 > 0## is all of the points in the plane outside that degenerate circle.
so the ans can't be x ≠0 , y≠0 ?
the correct ans is either (x^2) + (y^2) >0 or (x,y) ≠(0,0) which means x any y can't be 0 at the same time ?
 

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