B What is the effect of the twin paradoxon?

[Peter Strohmayer]

That's time dilation without any differential ageing.

A circular motion is complicated (where does the "time dialatation" come from, centripetal acceleration or relative motion?)

Let's stick with translational motion. Each of the twins is at the center of a long synchronized clock line. As the twins move past each other, they set the clocks directly in front of them - and thus their entire row of clocks - to "zero". The twin's clock continues to move past the other twin's row of clocks. Comparing the display of his clock with the display of the meeting clock, the twin notices that the display of his clock is lagging more and more behind the display of the just passing meeting clock. This is a symmetric process. Neither twin ages faster or slower as a result.

"It's time dilation without differential aging."

So what is the effect of the twin parodoxon? The acceleration of one twin!

 

[Ibix]

A circular motion is complicated (where does the "time dialatation" come from, centripetal acceleration or relative motion?)

You first need to define what you mean by time dilation in this context. I suspect @PeroK is using it to mean that "in the momentarily co-moving inertial frame of either observer the other one is always in motion and hence the other's clock is ticking slow". So in that case it obviously comes from relative motion.

If you mean something other than that by "time dilation" you need to define what you mean before the question can be answered.

This is a symmetric process. Neither twin ages faster or slower as a result.

More precisely, there is no way to answer which one is aging faster without picking a frame, and depending on which frame you pick the answer can be one, the other, or neither.

So what is the effect of the twin parodoxon? The acceleration of one twin!

All the acceleration does is invalidate a simple time-dilation based analysis, and allow the twins to meet up. There are at least two ways to do twin paradox type experiments without acceleration, and both still show differential aging effects - so the acceleration can't be that critical.

 

[Peter Strohmayer]

More precisely, there is no way to answer which one is aging faster without picking a frame, and depending on which frame you pick the answer can be one, the other, or neither.

In reference frame A, A would age slower than B, in reference frame B, B would age slower than A. This would be a contradiction, which is due to the fact that in the symmetrical situation described above, the lagging behind of clock displays compared to others is called "aging slower" or "... less time has passed". There is no justification whatsoever for making such speculations about the behavior of time.

The symmetry can only be broken by acceleration.

 

[Ibix]

In reference frame A, A would age slower than B, in reference frame B, B would age slower than A. This would be a contradiction,

No. This would be two different descriptions of the same thing. You can use the Lorentz transforms to switch between one and the other, so they are clearly not contradictory.

The symmetry can only be broken by acceleration.

As I said, there are at least two variations on the twin paradox that do not involve any acceleration but lead to differential aging.

 

[Dale]

A circular motion is complicated (where does the "time dialatation" come from, centripetal acceleration or relative motion?)

I disagree with this. It is circular motion that provides our most convincing experimental evidence for the clock hypothesis. This is precisely the hypothesis that there is no additional time dilation due to the acceleration that is not accounted for by the speed. In circular motion this hypothesis has been confirmed up to about $10^{18} \ g$

 

[Peter Strohmayer]

No. This would be two different descriptions of the same thing.

Of course, it is no contradiction if the clock of A lags behind one of the passing clocks of B, and if the clock of B lags behind one of the passing clocks of A.

But this is not what you claim.

The contradiction arises when the described facts are combined with speculative stories, e.g. that in unaccelerated motion A would age slower than B and B would age slower than A.

 

[Peter Strohmayer]

It is circular motion that provides our most convincing experimental evidence for the clock hypothesis.

I gladly believe you. But it irritates me that the twins move relative to each other and yet their watches always show the same time when they meet.

 

[Nugatory]

In reference frame A, A would age slower than B, in reference frame B, B would age slower than A. This would be a contradiction....

There is no contradiction here, just unclear thinking about what it means to say that one person is aging more slowly than another. The contradiction goes away when we define our terms carefully - including recognizing the relativity of simultaneity.

The symmetry can only be broken by acceleration.

Yet it is possible to construct a twin paradox situation that involves no acceleration at all, or when both twins experience identical accelerations.

 

[Peter Strohmayer]

just unclear thinking about what it means to say that one person is aging more slowly than another

I have no idea how I could have misunderstood the sentence, one ages slower than another, in view of the relativity of simultaneity.

 

[Ibix]

But this is not what you claim.

That is exactly what I claim. It was you who said it was a contradiction, in post #22. Either you have now changed your mind or you are discussing two different things and not making clear (at least to me) what you think is contradictory and what is not.

The contradiction arises when the described facts are combined with speculative stories,

Here's the problem: I don't know what you are calling "described facts" and what you are calling "speculative stories". You seem only to be describing two clocks in inertial motion and sometimes describing their behaviour as contradictory and sometimes not.

 

[Nugatory]

I have no idea how I could have misunderstood the sentence, one ages slower than another, in view of the relativity of simultaneity.

The assertion "A is aging more slowly than B" is equivalent to

At the same time that A's age is $A_0$ B's age is $B_0$. Later, at the same time that A's age is $A_0+\Delta T_A$ B's age is $B_0+\Delta B_T$, and $\Delta B_T\lt\Delta A_T$​

Clearly this will depend on the simultaneity convention used to define "at the same time"; the "A is aging more slowly than B" formulation serves only to obscure that dependency.

 

[Dale]

I gladly believe you. But it irritates me that the twins move relative to each other and yet their watches always show the same time when they meet.

Instead of being irritated, I look at this as an opportunity to demonstrate how these quantities can be calculated in an easy non-inertial frame to get consistent results.

In reference frame A, A would age slower than B, in reference frame B, B would age slower than A. This would be a contradiction

As others have stated, this is not a contradiction, but it is wrong. $$\frac{d\tau_A}{dt_A} > \frac{d\tau_B}{dt_A}$$ does not contradict $$\frac{d\tau_A}{dt_B} < \frac{d\tau_B}{dt_B}$$

 

[PeroK]

The symmetry can only be broken by acceleration.

Groan!

 

[Peter Strohmayer]

For example: consider the twins in the same circular orbit about a star or planet, but going in opposite directions. Each twin is moving relative to the other and each is continuously time dilated relative to the order. But, every time they pass each other their clocks show the same elapsed time.

Instead of being irritated, I look at this as an opportunity to demonstrate how these quantities can be calculated in an easy non-inertial frame to get consistent results.

Is the described counter-rotating circular motion perhaps equivalent to a mirror-image journey of two twins who start at the same time, turn the same distance and return at the same time (e.g. if their movements describe circles of the same size)?

 

[Peter Strohmayer]

You seem only to be describing two clocks in inertial motion and sometimes describing their behaviour as contradictory and sometimes not.

From the fact that the display of A's clock lags behind the display of one of B's passing clocks (which does not contradict a corresponding lag of B's clock), it cannot be concluded that A has aged more slowly than B (which, moreover, contradicts a corresponding slower aging of B). Even after a longer flyby, there is no change in the same age of A and B if they are treated equally in the sequence. When A and B meet again due to symmetric acceleration, they are still the same age.

 

[Peter Strohmayer]

Groan!

As described in #20, the reading of A's clock lags behind the readings of B's passing clocks, and the reading of B's clock lags behind the readings of A's passing clocks. This has nothing to do with differential aging. What would ever change in this result without acceleration?

There are at least two ways to do twin paradox type experiments without acceleration, and both still show differential aging effects - so the acceleration can't be that critical.

Will muons return?

 

[renormalize]

As I said, there are at least two variations on the twin paradox that do not involve any acceleration but lead to differential aging.

Can you expand on this statement by addressing a general question regarding travelers along two worldlines?

(Based on: https://sites.pitt.edu/~jdnorton/teaching/HPS_0410/chapters_May_30_2021/spacetime_tachyon/index.html)

Consider two observers $O_{1},O_{2}$ in flat spacetime, initially sharing the same worldline. At spacetime event $A$, their worldlines diverge and they each begin recording their proper-times and proper-accelerations. At event $B$, their worldlines re-converge and they compare readings. They find that their elapsed proper-times differ (i.e., they've experienced differential aging), so they rightly conclude that the individual worldlines they travelled between $A$ and $B$ must have different proper lengths. My question: are there any possible circumstances for which both $O_{1}$ and $O_{2}$ will have recorded no/zero proper accelerations between $A$ and $B$?

In other words: what possible mechanism in Minkowski spacetime, other than proper accelerations, can cause a difference in proper-lengths between two distinct worldline-segments that share common starting and ending points?

 

[jbriggs444]

In other words: what possible mechanism in Minkowski spacetime, other than proper accelerations, can cause a difference in proper-lengths between two distinct worldline-segments that share common starting and ending points?

Unless I am badly mistaken, in Minkowski spacetime two distinct geodesics can intersect only once.

You can make them intersect twice without a non-zero proper acceleration if you "bend" the rules with an event on a worldline where the proper acceleration is undefined. e.g. a clock handoff.

 

[PeterDonis]

Unless I am badly mistaken, in Minkowski spacetime two distinct geodesics can intersect only once.

You are not mistaken at all. This is correct; in fact it is at most once, since there are pairs of geodesics that do not intersect at all.

 

[renormalize]

Unless I am badly mistaken, in Minkowski spacetime two distinct geodesics can intersect only once.

Yes, that's really my point. Without accelerations, twins on different worldlines that started together can never meet again to compare ages. So I think we need to carefully distinguish between "differential aging where the twins start at event $A$ and end (or cross) at event $B$", which always requires acceleration (possibly infinite), and "differential aging where the twins never meet again". It's the later that I'd like see clarified to understand Ibix's statement that "...there are at least two variations on the twin paradox that do not involve any acceleration but lead to differential aging."

 

[PeterDonis]

Without accelerations, twins on different worldlines that started together can never meet again to compare ages.

This is true in flat Minkowski spacetime, as @jbriggs444 said, but it is not true in curved spacetime. In curved spacetime a pair of geodesics can cross more than once. Curved spacetime scenarios are probably what @Ibix was thinking of.

 

[Dale]

Is the described counter-rotating circular motion perhaps equivalent to a mirror-image journey of two twins who start at the same time, turn the same distance and return at the same time (e.g. if their movements describe circles of the same size)?

Yes. And as in that case you can use isotropy of the laws of physics to conclude that the readings will be the same.

what possible mechanism in Minkowski spacetime, other than proper accelerations, can cause a difference in proper-lengths between two distinct worldline-segments that share common starting and ending points?

The metric.

 

[PeroK]

Yes, that's really my point. Without accelerations, twins on different worldlines that started together can never meet again to compare ages. So I think we need to carefully distinguish between "differential aging where the twins start at event $A$ and end (or cross) at event $B$", which always requires acceleration (possibly infinite), and "differential aging where the twins never meet again". It's the later that I'd like see clarified to understand Ibix's statement that "...there are at least two variations on the twin paradox that do not involve any acceleration but lead to differential aging."

As has been explained in previous threads on this topic, acceleration is a physical constraint. The analogy is to claim that the hypotenuse of a right angle triangle is shorter than the sum of the other twin sides because of what happens to a pencil at the right angle corner. Rather than simply that the sum of the two lengths is greater..

Moreover, what is your explanation for more complicated scenarios where both twins accelerate? Do you have a complex system of measuring various accelerations and eventually determine which twin has aged more? Show me your equation for age based on proper acceleration! The alternative is simply to measure the length of each twin's worldline, which does not directly involve proper acceleration.

Finally, the same paradox can be described without acceleration, by the time measurement on the outbound journey being added to the time measurement on an inbound journey, with the turnaround being replaced by a passing of the baton, as it were. In this way, we see that the explanation is clearly and simply explained by the length of the different spacetime intervals. And, not necessarily by some mysterious force associated with proper acceleration.

 

[Peter Strohmayer]

You can make them intersect twice without a non-zero proper acceleration if you "bend" the rules with an event on a worldline where the proper acceleration is undefined. e.g. a clock handoff.

Please do not hand over any items from a moving car, including watches. The recipient could be injured. If you meant that a traveler shouts out the display of his watch to an oncoming traveler as he passes, that would be relativistic bookkeeping, but not physics.

 

[Peter Strohmayer]

It is circular motion that provides our most convincing experimental evidence for the clock hypothesis. This is precisely the hypothesis that there is no additional time dilation due to the acceleration that is not accounted for by the speed.

(The twins describe circles of the same size) Yes. And as in that case you can use isotropy of the laws of physics to conclude that the readings will be the same.

Then, in my opinion, the experimental evidence for the clock hypothesis is based on accelerated motion. I am not saying that the acceleration would cause an "additional time dilation", but that the detection of the time difference presupposes a return, and this return presupposes an acceleration.

 

[Ibix]

In other words: what possible mechanism in Minkowski spacetime, other than proper accelerations, can cause a difference in proper-lengths between two distinct worldline-segments that share common starting and ending points?

There are three scenarios that I was thinking of, although only one meets your criteria.

The first is to use curved spacetime, as others have noted. The traveller swings round a black hole and returns, having been inertial at all times. Yet their age is different.

The second is sometimes called the "triplet paradox", although that's a misnomer. You have three eternally inertial observers with speeds $0, \pm v$ arranged so that they don't all meet at the same time. Each observer records their proper time between meetings. You will find that the ratio between the sum of the shorter times and the longer time is the same $\gamma$ you would see in a twin paradox. Geometrically, this is because a triangle has the same properties whether you choose to extend the line segments making up its sides through the vertices or not. Physically this shows that the proper time of the travelling twin is the same as two inertial observers temporarily co-moving with him, so acceleration can't be the cause of the shorter time.

The third does meet your specifications. You use flat spacetime with a non-trivial topology - you give space two edges, then identify the edges. On a Minkowski diagram this is equivalent to printing it out and rolling it up into a cylinder with the time axis along the cylinder. Any pair of inertial observers with non-zero relative speed will meet repeatedly having experienced different elapsed times (except the special case where their velocities are equal and opposite in the frame whose timelike axis is along the cylinder), and again with no acceleration. The spacetime is still flat in the relevant sense.

 

[Ibix]

If you meant that a traveler shouts out the display of his watch to an oncoming traveler as he passes, that would be relativistic bookkeeping, but not physics.

You are saying that adding two quantities together and comparing them to a third is not physics? Is that a general rule for you?

 

[Peter Strohmayer]

I don't mean that apodictically. The transfer of the information about the display of the clock allows the calculation of a "slower aging", but to be really younger than his brother, the twin must return himself.

 

[Ibix]

but to be really younger than his brother, the twin must return himself.

Sure. But that only requires acceleration in flat spacetime with a trivial topology, and it doesn't mean acceleration causes differential aging.

 

[Peter Strohmayer]

Curved spacetime also leads to acceleration via gravity and equivalence. It is sufficient and simpler to analyze the twin paradox from the point of view of SRT.