What is the Electric Potential at a Point on the Surface of a Charged Sphere?

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Homework Help Overview

The discussion revolves around calculating the electric potential at a point on the surface of a conducting charged sphere when a point charge is placed outside it. The problem involves understanding the effects of induced charges on the sphere and the application of image charge methods.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the concept of induced charges and their effect on the electric potential, with some suggesting the use of image charge methods to simplify the problem. Questions arise regarding the distribution of charges on the sphere and the validity of the image charge approach.

Discussion Status

There is an ongoing exploration of the image charge method and its implications. Some participants express skepticism about the necessity of this method for the problem at hand, while others clarify the role of induced charges and the conditions under which the electric field behaves as described.

Contextual Notes

Participants question the initial conditions of the sphere, particularly its neutrality and the resulting charge distribution upon the introduction of the external point charge. There is also a discussion about the assumptions related to the behavior of charges in a conductor.

utkarshakash
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Homework Statement


A point charge q is placed at a distance 2r from the centre O of a conducting charged sphere of radius r. Due to the induced charges on the sphere, find the electric potential at point P on the surface of sphere(it is at a distance 3r from q) (if Kq/r = 18 volt)

Homework Equations



The Attempt at a Solution


Due to the induced charges the potential will be 0 as there are as many -ve charge on the surface of sphere as that of +ve charge. So the net potential is due to q which comes out to be 6 but correct answer is 3.
 
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This is best handled by image methods. Given the location of q outside your sphere, where and what size& polarity is the image charge inside the sphere? Then you dump the sphere and work with just the two point charges.
 
rude man said:
This is best handled by image methods. Given the location of q outside your sphere, where and what size& polarity is the image charge inside the sphere? Then you dump the sphere and work with just the two point charges.

How can there be a net charge on the sphere when it is initially neutral? It must be zero. Half of the sphere will contain -ve charge and the other half, +ve charge.
Also what do you mean by image methods?
 
As I said, once the image charge is in place the sphere is gone. So there is no charged sphere or any other kind.

The function of the image charge is to geneate a field that is indistinguishable from the charge-redistributed sphere at the point of observation. The so-synthesized field is invalid for regions inside the sphere since the field inside a pure conductor has to be zero.
 
rude man said:
As I said, once the image charge is in place the sphere is gone. So there is no charged sphere or any other kind.

The function of the image charge is to geneate a field that is indistinguishable from the charge-redistributed sphere at the point of observation. The so-synthesized field is invalid for regions inside the sphere since the field inside a pure conductor has to be zero.

I don't think that this simple problem requires me to use such kind of methods.
 
utkarshakash said:

The Attempt at a Solution


Due to the induced charges the potential will be 0 as there are as many -ve charge on the surface of sphere as that of +ve charge. So the net potential is due to q which comes out to be 6 but correct answer is 3.

The number of charges are same but they aren't uniformly distributed due to polarization. They will produce a potential.
 

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