What Is the Electron's Momentum After Compton Scattering?

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SUMMARY

The discussion focuses on calculating the momentum of an electron after Compton scattering when a photon with a wavelength of 0.1050 nm collides with it at a 60-degree angle. The correct approach involves applying conservation of momentum in both the x and y directions, as the scattering angle of the photon does not directly dictate the electron's momentum direction. Participants emphasized the importance of using the correct equations for the momentum of the photon before and after scattering, specifically noting that the x-component of momentum must account for the angle of scattering.

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  • Understanding of conservation of momentum principles
  • Familiarity with Compton scattering concepts
  • Knowledge of photon momentum calculations using the equation h/λ
  • Basic understanding of relativistic effects in particle physics
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  • Learn how to apply conservation of momentum in two dimensions
  • Explore the relationship between photon wavelength and energy
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oldspice1212
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A photon with wavelength lambda = 0.1050 nm is incident on an electron that is initially at rest. If the photon scatters at an angle of 60.0 degrees from its original direction, what are the magnitude and direction of the linear momentum of the electron just after the collision with the photon?

Hey guys, was wondering if someone could help me out with this, I understand I have to use conservation of momentum, so I have for x direction (I'll be using y for lambda here): h/y=h/y'+Pecos(theta)

so Pe =cos theta( h/y-h/y' ) but this seems to be wrong, I'm not sure why, I just need to understand why this isn't right, thanks.
 
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oldspice1212 said:
I understand I have to use conservation of momentum, so I have for x direction (I'll be using y for lambda here): h/y=h/y'+Pecos(theta)

##\small h/\lambda## is correct for the x-component of momentum of the incident photon. But ##\small h/\lambda '## is not correct for the x-component of momentum of the photon after the scattering. It goes off at a ##\small 60^o## angle.
 
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Oh thank you very much I see where I made my mistake :)
 
Also, note that the photon scattering at 60 degrees does not mean the electron does. You need to use conservation in both directions to find the linear momentum components of the electron. After that you have to find some way of also extracting the wavelength of the photon after scattering.

Also, I really suggest that you use the homework template and fill in the relevant equations. This problem can be tackled with different levels of sophistication depending on how much relativity you know.
 
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Orodruin said:
Also, note that the photon scattering at 60 degrees does not mean the electron does. You need to use conservation in both directions to find the linear momentum components of the electron. After that you have to find some way of also extracting the wavelength of the photon after scattering.

Also, I really suggest that you use the homework template and fill in the relevant equations. This problem can be tackled with different levels of sophistication depending on how much relativity you know.

Thanks, but I figured it out :)!
 

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