What is the energy of one of the orange light photons?

In summary, the Argon gas laser produces orange light with a wavelength of 6.3E-7 meters and a frequency of 4.76E14 Hz, with an output of 5.2 mW. The energy of one photon of this light is 6.6E-34 Joules, and the momentum is 1.05E-27 kg*m/s. The laser emits 1.66E15 photons per second, and there is no direct relationship between the frequency and the number of photons per second.
  • #1
FateEternal
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The Argon gas laser produces orange light of wavelength 6.3E-7 meters and of frequency 4.76E14 Hz. The laser output is 5.2 mW
a. What is the energy of one of the orange light photons?
b. What is the momentum of one of the orange light photons?
c. How many photons per second does this laser emit?
d. What is the realtionship between (c) and the frequency of the light
 
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  • #2
a. the energy of a photon is hf.
b.
from special relativity [tex]E^2=m^2c^4+p^2c^2[/tex]
since the rest mass of a photon is zero, it becomes [tex]E=pc[/tex]
so, [tex]p = \frac{E}{c}[/tex]
since [tex]E = hf = h (\frac{c}{\lambda})[/tex],
[tex]p = (\frac{hc}{\lambda}) *(\frac{1}{c})[/tex]
[tex]p = \frac{h}{\lambda} [/tex]
c. okay, you know the energy per second the laser emmits right?
how many times the energy of a single photon is it?
d. what's the relation between f and c? (hint: you can find it on this post...)
 
Last edited:
  • #3
a 6.6E-34(4.76E14)
=3.14E-19
b p=6.6E-34/6.3E-7
=1.05E-27
c 5.2E-4/3.14E-19
=1.66E15
d ...i can't see a relation between
1.66E15 photons per second
and 4.76E14 Hz
unless i did something wrong
 

1. What is meant by the energy of a photon?

The energy of a photon refers to the amount of electromagnetic radiation it carries. It is directly proportional to the frequency of the radiation, meaning that higher frequency photons carry more energy than lower frequency ones.

2. How is the energy of a photon related to its wavelength?

The energy of a photon is inversely proportional to its wavelength. This means that shorter wavelength photons, such as blue or violet light, have higher energy than longer wavelength photons, such as red or orange light.

3. What is the unit of measurement for photon energy?

The unit of measurement for photon energy is electron volts (eV). This unit is commonly used in physics to measure the energy of subatomic particles and photons.

4. What is the energy of one orange light photon in electron volts?

The energy of one orange light photon is approximately 2.2 electron volts (eV). This value can vary slightly depending on the exact wavelength of the orange light.

5. How is the energy of a photon calculated?

The energy of a photon can be calculated using the formula E = hf, where E is energy in joules, h is Planck's constant (6.626 x 10^-34 joule seconds), and f is frequency in hertz. Alternatively, the formula E = hc/λ can be used, where c is the speed of light (3 x 10^8 meters per second) and λ is wavelength in meters.

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