What is the energy of the lowest orbital and why?

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SUMMARY

The energy of the lowest orbital, known as the ground state energy, is determined by quantum mechanics and is specific to each atom. For hydrogen, this energy is -13.6 eV. When an electron transitions from the second to the first orbital, the wavelength of the emitted photon is inversely related to the energy difference between these states. Among the options provided, the bipositive lithium ion (Li²⁺) will emit the photon with the smallest wavelength due to its higher nuclear charge, resulting in a greater energy difference during the transition.

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Help needed!

Could someone please answer the folloing questions.
Plese do give the explanations too

2- What is the energy of the lowest orbital and why?

3- If an electron makes a transition from 2nd to the first orbital than in which of the following particles will the wavelength of the photon released will be the smallest.
a) Hydrogen atom b) Deutrium atom c) Helium ion d) bipositive lithium ion.
 
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