What is the Energy Transfer in a Copper-Water System?

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SUMMARY

The discussion focuses on the energy transfer in a copper-water system involving a copper vessel, water, and a copper lump. The copper vessel has a mass of 0.1 kg, containing 0.2 kg of water initially at 25°C, which rises to 45°C after the copper lump is introduced. The specific heat capacity of the copper lump is 400 J kg-1°C-1. The energy gained by the water and the copper vessel is equal to the energy lost by the copper lump, allowing for the calculation of the original temperature of the copper lump based on these energy exchanges.

PREREQUISITES
  • Understanding of specific heat capacity
  • Knowledge of the formula E=mcΔt for energy calculations
  • Familiarity with thermal equilibrium concepts
  • Basic principles of heat transfer
NEXT STEPS
  • Calculate energy gained by water using E=mcΔt
  • Determine energy gained by the copper vessel using E=mcΔt
  • Find energy lost by the copper lump and its original temperature
  • Explore thermal equilibrium in multi-body systems
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Students and professionals in physics, thermodynamics enthusiasts, and anyone studying heat transfer principles in thermal systems.

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A copper vessel of mass 0.1 kg contains 0.2 kg
of water at 25°C. A lump of copper which had
stayed in a furnace for some time is transferred
quickly from the furnace into the water. The
temperature of water rises to 45°C finally. The
massof the copper lump is 0.1 kg and its specific
heatcapacity is 400 J kg-1°C-I.
(a) Find the energy gained by the water.
(b) Findthe energy gained by the copper vessel.
(c) Find the energy lost by the copper lump.
(d) What do you assume when you obtain the
answer in (c)?
(e) Estimatethe temperature of the furnace.
 
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And what have you tried?

Remember, heat gained by something = heat lost by something else.

Table of specific heats,
http://hyperphysics.phy-astr.gsu.edu/hbase/tables/sphtt.html#c1

In the end, the water, the copper vessel, and the copper lump all are at the same temperature.
Find the amount of energy it took to heat the water and copper vessel up to the final temperature, this is the amount of heat energy the copper lump lost, you can then figure out the original temperature of the copper lump.
 
Remember,
energy gained by the water + energy gained by the copper vessel =energy lost by the copper lump
and E=mc△t , which m=mass, c= specific heat capacity , △t=change in temperature , E=energy
 

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