Solving for Final Equilibrium Temperature of Water-Copper System

[Sam Vermeulen]

Homework Statement

173 g of water at 20°C is contained in a copper container of mass 327 g. An additional 129 g of water at 100°C is added. What is the final equilibrium temperature (in degrees C) if we treat the system's water and container as isolated?

Homework Equations

Q = mcΔT

The Attempt at a Solution

0 = m_water1c(T_f - T_i) + m_water2c_water(T_f - T_i) + m_copperc_copper(T_f - T_i)
0 = (.173kg)(4.186kJ/kg°C)(T_f - 20°C) + (0.129kg)(4.186kJ/kg°C)(T_f - 100°C) + (.327kg)(.387kJ/kg°C)(T_f - 20°C)

I attempted to solve for T_f but the answer was not correct.

 

[kuruman]

Hi Sam Vermeulen and welcome to PF.

The method is correct. Recheck your algebra.

 

[Sam Vermeulen]

Hi Sam Vermeulen and welcome to PF.

The method is correct. Recheck your algebra.

Thank you! I figured out where I was going wrong. Much appreciated.