What is the equation for calculating terminal velocity?

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The discussion focuses on calculating terminal velocity, emphasizing that it represents the maximum speed of a falling object. The equation provided, v = (g/β)(e^(-βt) - 1), describes velocity as a function of time, with terminal velocity reached as time approaches infinity. It is noted that while theoretical formulas exist, constants like β must be determined experimentally. The relationship between gravitational force and drag force is highlighted, with the equation mg - D = ma illustrating that acceleration becomes zero at terminal velocity. Understanding these concepts is crucial for accurately calculating terminal velocity in various contexts.
ElDavidas
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hi again,

I'm pretty sure I understand the concept of terminal velocity in that there is an upper limit to the speed of a falling body. How do you calculate the terminal velocity of an equation?

For example:

v = \frac {g} {\beta}( e^{- \beta t} - 1)

v represents velocity
 
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Don't know what you mean by "terminal velocity of an equation", but if that expression gives the speed as a function of time then just let t \rightarrow \infty.
 
What does all that represent?
 
Hi ElDavidas

I think that understand your question. I just know that this concept is relative, it means, in the context of falling bodies the formulae could be deduced theoretically, but however, the constants like your beta is determined only experimentally. Do you like another answer or is sufficient?
 
I think you need the terminal velocity of a free falling object. For any fluids, here air we have an equation that CpAv^2 = D where D is the drag force applied by the fluid on the object in a direction opposite to the relative motion of the first object. Now mg - D = ma. So a becomes zero when?(better now you do the rest) So that is how you get it.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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