What is the equation for constructive interference in thin film interference?

Click For Summary

Homework Help Overview

The problem involves thin film interference between two pieces of glass with a water film in between. The original poster seeks to determine the wavelengths of light that can be seen in both transmitted and reflected light under normal incidence of white light.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster expresses uncertainty about how to approach the calculation for transmitted light and questions the applicability of interference in this context. Other participants suggest that energy conservation principles apply and discuss the conditions for constructive interference.

Discussion Status

Participants are exploring different interpretations of the interference phenomena in transmitted and reflected light. Some guidance has been offered regarding the conservation of light energy and the conditions for constructive interference, but there is no explicit consensus on the approach to take.

Contextual Notes

The original poster mentions specific wavelengths that can be seen in the transmitted and reflected light, indicating a focus on visible light ranges. There is also a hint of confusion regarding the role of reflections in transmitted light, which remains an area of exploration.

fedecolo
Messages
61
Reaction score
1

Homework Statement


Between two pieces of glass (##n_1=1.70##), there is a thin film of water (##n_2=1.33## and width ##d=1 \mu m##). If there is normal-incidence of white light on the water surface, find:
(a) which wavelenghts can be seen in the light transmitted (answer: 667 nm,533 nm,444 nm, 381 nm)
(b) which wavelenghts can be seen in the light reflected (answer: 593 nm,484 nm, 410 nm, (355 nm) )

The Attempt at a Solution


(a) I don't know how to deal with light transmitted
(b) I set the ##2d= \left(m-\frac{1}{2} \right) \cdot \frac{\lambda}{n_2}## to find the lambdas for ##m=1,2...## but I obtain only ##\lambda_{m=1}=355 nm## (below the light that can be seen).

Any help?
 
Physics news on Phys.org
fedecolo said:
(a) I don't know how to deal with light transmitted
You can assume that none of the light is absorbed by the material. So, the total amount of incoming light energy must be conserved. As less light is reflected, more light must be transmitted. And vice versa.

(b) I set the ##2d= \left(m-\frac{1}{2} \right) \cdot \frac{\lambda}{n_2}## to find the lambdas for ##m=1,2...## but I obtain only ##\lambda_{m=1}=355 nm## (below the light that can be seen).
Your equation looks OK. But, in order to get a wavelength of 355 nm, I have to let m = 8. You will need to choose values of m that yield visible wavelengths.
 
TSny said:
You can assume that none of the light is absorbed by the material. So, the total amount of incoming light energy must be conserved. As less light is reflected, more light must be transmitted. And vice versa.

Thanks. But how can I set the equation for the constructive interference in the first case? There is no interference since the light is transmitted(?)
 
fedecolo said:
Thanks. But how can I set the equation for the constructive interference in the first case? There is no interference since the light is transmitted(?)
There is always interference (constructive, destructive, or something in between) in the transmitted waves and in the reflected waves. Standard textbooks show how you get two reflected rays that interfere. See if you can show how to get two transmitted waves that interfere. Hint: One of the transmitted rays has no reflections. The other transmitted wave has more than one reflection.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
3K
Replies
7
Views
6K
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
2
Views
4K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 9 ·
Replies
9
Views
4K