What is the equation for finding the energy of a photon in a Σ0 decay?

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SUMMARY

The energy of a photon produced in the decay of a Σ0 baryon can be calculated using conservation of momentum and energy principles. The Σ0 baryon, with a mass of 1193 MeV/c², decays into a Λ0 baryon (mass 1116 MeV/c²) and a photon (ɣ). The energy of the photon can be derived from the difference in mass between the Σ0 and Λ0, accounting for the kinetic energy shared between the Λ0 and the photon. The relevant equation to find the energy of the photon is E = mc², where m is the effective mass-energy difference.

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Homework Statement



The sigma Baryon Σ0 is at rest and decays to form an Λ0 and a ɣ photon.




Homework Equations


Mass of Σ0 is 1193 MeV/c^2
Mass of Λ0 is 1116 MeV/C^2


The Attempt at a Solution


K obviously since the Σ0 is at rest, momentum must be conserved and the Λ0 and ɣ go in completely opposite directions to each other.

Since the Σ0 weighs more than the Λ0, I can assume it's rest mass go towards the rest mass of the Λ0 and provides kinetic energy for the Λ0.. Also giving energy out as the ɣ.

But the ɣ has no mass. So it's energy is it's momentum. But I've forgotten how to account for that. What equations do I use to found out how much energy the photon has.

The only thing I have going is that 77MeV/c^2 is shared between the kinetic energy of the Λ0 and the total energy of the ɣ photon, but I don't know how to work out HOW MUCH is shared between them.

Please help lol.
 
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Sorry forgot some of the question:

Find the energy of the Photon and the Total Energy of the Λ0
 
Bump?

I'm sure this will take you guys under a minute when compared to the other questions here. I just want an equation or a push in the right direction thanks.
 

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