Special relativity - kinematics

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SUMMARY

The discussion focuses on the kinematics of a photon colliding with a proton at rest, resulting in the reaction $$\gamma + p \rightarrow n+\pi^+$$. The threshold energy of the photon is derived using the invariance of total momentum squared, yielding the equation $$E=m_\pi + \frac{m_\pi^2}{2m}$$. Additionally, the mean lifetime of the pion in the laboratory frame is calculated using the Lorentz factor, where $$\tau=\gamma \tau_0$$, confirming that both particles move with the same velocity in the lab frame at threshold energy.

PREREQUISITES
  • Understanding of special relativity concepts, particularly Lorentz transformations
  • Knowledge of particle physics, specifically the properties of protons, neutrons, and pions
  • Familiarity with conservation laws in physics, including momentum and energy conservation
  • Ability to manipulate equations involving relativistic energy and momentum
NEXT STEPS
  • Study the derivation of threshold energy in particle collisions
  • Learn about Lorentz transformations and their applications in particle physics
  • Explore the concept of mean lifetime and time dilation in special relativity
  • Investigate the conservation of momentum and energy in relativistic collisions
USEFUL FOR

Students and educators in physics, particularly those focusing on special relativity and particle physics, as well as researchers analyzing particle collision events.

Aleolomorfo
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Homework Statement


A photon hits a proton at rest in the laboratory frame and there is the process:
$$\gamma + p \rightarrow n+\pi^+$$
The mass of the pion is ##m_\pi## and assuming that the masses of the proton and the neutron are the same (##m##):
  1. Finding the threshold energy of the foton;
  2. At the threshold energy, finding the mean lifetime of the pion in the laboratory frame knowing that the mean lifetime at rest is ##\tau_0##

Homework Equations

The Attempt at a Solution


For the first point I have used the invariance of the total momentum squared bewtween the lab frame before the collision and the CM frame after the collision (particle at rest) and my result is:
$$E=m_\pi + \frac{m_\pi^2}{2m}$$
I think this is correct.
For the second part I need a confirmation about my reasoning. I need to calculate the pion's velocity in the lab and then ##\tau=\gamma \tau_0##. Since at the minimum energy the particles are at rest in the CM frame, is it correct to state that in the lab frame they move with the same velocity along the same direction(both to the right or equivalently to the left)? If this assumption is correct I can use the conservation of the energy ##E+m=m\gamma+m_{\pi}\gamma##. From this relation I can find ##\gamma## and so ##\tau##. Is it correct?
 
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It all looks correct to me.
 
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Likes   Reactions: Aleolomorfo
TSny said:
It all looks correct to me.
Perfect, thank you!
 

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