Relativistic Energy and Velocity

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SUMMARY

The discussion focuses on calculating the speed, momentum, and total energy of a proton with a mass of 938 MeV/c² and a kinetic energy of 1760 MeV. The relevant equations include E=mc² for rest energy, E=Ɣmc² for total energy, p=Ɣmv for momentum, and KE=mc²(Ɣ-1) for kinetic energy. The user initially struggled to interpret the significance of the 1760 MeV value but successfully assumed it represented kinetic energy, leading to a correct solution.

PREREQUISITES
  • Understanding of relativistic physics concepts
  • Familiarity with the equations of energy and momentum in special relativity
  • Knowledge of the Lorentz factor (Ɣ)
  • Basic proficiency in manipulating units of energy (MeV) and mass (MeV/c²)
NEXT STEPS
  • Study the derivation and application of the Lorentz factor (Ɣ)
  • Learn how to calculate relativistic momentum using p=Ɣmv
  • Explore the relationship between kinetic energy and total energy in relativistic contexts
  • Investigate examples of particle physics problems involving protons and other subatomic particles
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Students and educators in physics, particularly those focusing on special relativity, as well as anyone interested in particle physics and energy calculations involving high-energy particles.

PhysicsInNJ
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Homework Statement


A proton has a mass of 938 MeV/c2. Calculate the speed, momentum, and total energy of a 1760 MeV proton.

Homework Equations


E= mc^2 (Rest Energy)
E= Ɣmc^2 (Total Energy)
p= Ɣmv (momentum)
KE= mc^2(Ɣ-1) (Kinetic Energy)

The Attempt at a Solution


I'm not sure how the last number given (1760 MeV) is relevant, as in, I don't know what to do with it in order to start solving the problem. I know it isn't rest energy/mass because that is given as 938 MeV/c^2. It also is not the total energy because that is asked for in the question and the answer is not 1760 MeV.
 
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Normally I would think they meant the total energy, but perhaps they meant the kinetic energy. Try assuming the kinetic energy is 1760 MeV and see what you get.
 
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Lucas SV said:
Normally I would think they meant the total energy, but perhaps they meant the kinetic energy. Try assuming the kinetic energy is 1760 MeV and see what you get.
You're right. that worked. Thank you!
 
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