What is the escape velocity for an object

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SUMMARY

The escape velocity for an object on the surface of a planet with a mass of 1.9x1027 kg and a radius of 7.2x107 m is calculated using the formula Ve = √(2GM/r). By substituting the given values into the equation, the correct escape velocity is determined to be 5.9x104 m/s. The discussion emphasizes the importance of unit consistency in calculations to avoid errors.

PREREQUISITES
  • Understanding of gravitational constant (G)
  • Familiarity with the formula for escape velocity
  • Basic algebra for manipulating equations
  • Knowledge of units of measurement in physics
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  • Learn about the implications of escape velocity in space travel
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Homework Statement


What is the escape velocity for an object on the surface of a 1.9x10^27kg planet of radius 7.2x10^7m?


Homework Equations


Ve = √2GM/r



The Attempt at a Solution


What I did was take the values for the mass and radius directly from the question then I plugged them into the above equation and the answer I got is 5.9x10^4m/s.

I was just wondering is this correct or am going wrong somewhere because it seems like there is more to this question?
 
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There's not much to this problem, is there. :)

I would say one thing, for future reference, keep an eye on the units.
 

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