What is the Factorization of p^3 - q^3 -p(p^2 - q^2) + q(p - q)^2?

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SUMMARY

The factorization of the expression p^3 - q^3 - p(p^2 - q^2) + q(p - q)^2 simplifies to pq(p - q). The solution process involves rearranging the terms and applying the difference of cubes formula. The final verification confirms that the factorization is accurate, demonstrating a clear understanding of algebraic manipulation and factorization techniques.

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mathdad
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Factor.

p^3 - q^3 -p(p^2 - q^2) + q(p - q)^2

Solution:

p^3 - q^3 - p^3 + pq^2 + q(p^2 -2pq + q^2)

p^3 - q^3 - p^3 + pq^2 + qp^2 -2pq^2 + q^3

pq^2 + qp^2 - 2pq^2

-pq^2 + qp^2

qp^2 - pq^2

pq(p - q)

Correct?
 
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Let's see:

$$p^3-q^3-p(p^2-q^2)+q(p-q)^2=(p-q)\left(\left(p^2+pq+q^2\right)-p(p+q)+q(p-q)\right)=(p-q)(p^2+pq+q^2-p^2-pq+pq-q^2)=pq(p-q)\quad\checkmark$$
 
It feels good to find the right answer.
 

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