The problem involves a 97.6-g lead ball dropped from a height of 4.57 m, with an initial temperature of 20°C. The scenario describes a totally inelastic collision with the ground, where the kinetic energy of the ball is assumed to convert entirely into thermal energy, raising the ball's temperature. Participants are seeking to understand the steps to find the final temperature of the ball after the drop.
The discussion includes attempts to apply relevant equations, with some participants expressing uncertainty about their calculations. There is a mix of guidance and requests for confirmation on the proposed methods, indicating an ongoing exploration of the problem.
Participants are reminded to adhere to forum rules regarding providing attempts and avoiding direct answers, which influences the nature of the discussion.
Silverbolt said:A 97.6-g lead ball with an initial temperature of 20°C, is dropped from rest from a height of 4.57 m. The collision between the ball and ground is totally inelastic. Assuming all the ball's kinetic energy goes into heating the ball, find its final temperature.
PLEASE HELP ME UNDERSTAND THIS PROBLEM STEP-BY-STEP
That should work.Silverbolt said:This is what I think I would do:
So I would us the potential energy equation: P.E.=mgh
so --> P.E.= (.0976 kg)(9.8m/s^2)( 4.57m)
P.E. = 4.371J
With this I'll use the equation: Q=mcT
4.371J =(.0976kg)(128 J/Kg(°C) )( Tf-20°C)
Ans so I'll solve for Tf
SO IS THIS RIGHT?? PLEASE HELP