What is the final velocity of the ball?

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    Ball Collision
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Homework Help Overview

The discussion revolves around a physics problem involving a ball colliding with a wall at an angle of 60 degrees. The participants are examining the momentum of the ball before and after the collision, as well as the forces involved during the impact.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to calculate the momentum of the ball before and after it strikes the wall, questioning how time factors into the calculations. There are discussions about the correct application of momentum equations and the geometry involved in the problem.

Discussion Status

There is an ongoing exploration of the relationship between the momentum before and after the collision, with some participants providing hints and corrections regarding the calculations. The discussion is dynamic, with multiple interpretations being considered, particularly around the geometry of the situation and the role of time in the calculations.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is also a focus on ensuring that the calculations align with the physics principles being discussed.

rzlblrt417
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Homework Statement



a ball hits a wall at 60 degrees from the wall and leaves the wall at 60 degrees.

v1 = 10 m/s
v2 = 10 m/s
m = 3.00 kg
t = 0.200s

Homework Equations



p = mvcos(angle)
J = p2 - p1


The Attempt at a Solution



p = (3.00)(10)(cos(60))
p1 = 15
p2 = 15

and that is as far as i can get. I am not sure how time plays into this. Any help is appreciated. I have the text in a few hours. Thank you
 
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what is being asked for?
 
rzlblrt417 said:

Homework Statement



a ball hits a wall at 60 degrees from the wall and leaves the wall at 60 degrees.

v1 = 10 m/s
v2 = 10 m/s
m = 3.00 kg
t = 0.200s

Homework Equations



p = mvcos(angle)
J = p2 - p1


The Attempt at a Solution



p = (3.00)(10)(cos(60))
p1 = 15
p2 = 15

and that is as far as i can get. I am not sure how time plays into this. Any help is appreciated. I have the text in a few hours. Thank you


As grzz said , I cannot understand what you are trying to find out. Anyways what's the question asking for ?
 
My apologies, I always do that. Force on by the wall on ball
 
*by wall on the ball
 
rzlblrt417 said:
*by wall on the ball

Got that ! Ok so what is p1 ? Or I mean momentum of the ball before striking the wall ?

Then you find out p2 or the momentum of ball after it stroke the wall.

What do you get ?
 
sankalpmittal said:
Got that ! Ok so what is p1 ? Or I mean momentum of the ball before striking the wall ?

Then you find out p2 or the momentum of ball after it stroke the wall.

What do you get ?

the same thing for p1 as p2?
 
14.7n?
 
rzlblrt417 said:
the same thing for p1 as p2?

No p1 and p2 aren't same. Be careful regarding geometry.

Hint : see the image : http://postimage.org/image/qvnhzhnsl/

Above answer is wrong.
Look at image
 
Last edited by a moderator:
  • #10
sankalpmittal said:
No p1 and p2 aren't same. Be careful regarding geometry.

Hint : see the image : http://postimage.org/image/qvnhzhnsl/

ok so then

p1 = (3.00)(10)cos(30)
p2 = (3.00)(10)cos(60)

so p2 - p1 = -14.133 so then it would just be 14.133N?

or is it sin(30) making it 14.5N
 
Last edited by a moderator:
  • #11
rzlblrt417 said:
ok so then

p1 = (3.00)(10)cos(30)

Correct.

p2 = (3.00)(10)cos(60)

Right !

so p2 - p1 = -14.133 so then it would just be 14.133N?

or is it sin(30) making it 14.5N

Nope. What about time t ?
From Newton's second law : F= Δp/Δt = p1-p2/t

Plug in it. What do you get ?
Do calculations properly. You got it wrong for p1-p2 also.
 
  • #12
sankalpmittal said:
Correct.



Right !



Nope. What about time t ?
From Newton's second law : F= Δp/Δt = p1-p2/t

Plug in it. What do you get ?
Do calculations properly. You got it wrong for p1-p2 also.

OH! ok so then after plugging everything in i got 71.6N!
 
  • #13
rzlblrt417 said:
OH! ok so then after plugging everything in i got 71.6N!

Your method of evaluation is correct but calculations are wrong. Do you know the value of cos 60o and cos 30o ? What are they ?
 

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