What is the Force on a Rectangular Loop in a Magnetic Field?

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Homework Help Overview

The discussion revolves around calculating the net force on a rectangular loop of wire situated in a magnetic field created by two currents, I1 and I2. The parameters include distances and current values, with the original poster attempting to determine the force's magnitude and direction, as well as the induced emf due to a change in current.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster calculates forces based on the magnetic field generated by I1 and questions the validity of their results. Participants discuss the relationship between the magnetic field strength and distance, and the implications for force calculations. There is also inquiry into the reasoning behind induced currents and their directions.

Discussion Status

Participants have engaged in clarifying the calculations and reasoning presented. Some express agreement with the original poster's findings, while others raise questions about potential errors and the assumptions made regarding the system. The discussion reflects a collaborative effort to explore the problem without reaching a definitive conclusion.

Contextual Notes

There is mention of a diagram that some participants could not initially access, which may affect the clarity of the discussion. Additionally, the original poster notes a grading error related to their solution, suggesting that there may be discrepancies in the problem setup or interpretation.

fogvajarash
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Homework Statement


Let d = 0.048m, L = 0.15m, r = 0.10m in the following diagram. Assume that the current I1 = 80.0A and I2 = 40.0A. Find the net force on the rectangle of wire and the direction it points, and state the direction of the emf if the current I1 is increasing in the direction of the arrow.

Diagram: http://imgur.com/RmvkO9n

Homework Equations


-


The Attempt at a Solution


I have that the force is given by F = BIl. In this case, B would come from the field created by the current I1. So, we would get that the force will be (let force 1 be for the closest part of the loop and force 2 for the farthest part of the loop):

F1 = \frac{μI<sub>2</sub>I<sub>1</sub>l}{2πd} ≈ -2x10-3N
F2 = \frac{μI<sub>2</sub>I<sub>1</sub>l}{2π(d+r)} ≈ 6.49x10-4N

Then, the net force would be Fnet = -1.35x10-3N, pointing downwards. However, I get a mistake. Why is this the case? I'm thinking that my procedure is right until now, as there will be no force felt by the loop wires perpendicular to the long wire. I tried to perhaps calculate an induced current, but I can't do so as I don't have a resistance.

For the second part, the current would be induced to even out the flux change, so the induced B field should point down, leading to an opposite direction of the induced current as stated in the diagram. This is because the flux of the long wire would be increasing upwards in the plane of the wire.
 
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Hi foggy, I can't see the diagram you are referring to !
 
BvU said:
Hi foggy, I can't see the diagram you are referring to !

So sorry! I have uploaded it right now.
 
I would expect B to be smaller at r+d than at d, so |F| too. Wouldn't you ?

I suppose the -3 is really a -4 ?

How do you know you get a mistake ?

With ##\mu = 4\pi 10^{-7}## I get the same as you...
 
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BvU said:
I would expect B to be smaller at r+d than at d, so |F| too. Wouldn't you ?

I suppose the -3 is really a -4 ?

How do you know you get a mistake ?

With ##\mu = 4\pi 10^{-7}## I get the same as you...

My bad again sorry. The computer system is telling me that I have made a mistake (I'm not sure where though). In the meantime, is my reasoning for the flux current correct? Thanks for your time and patience.
 
Well, as I said, same result: same value, same direction.

Your reasoning for the induced emf is right, too. Since they don't tell us how the I2 comes about, there isn't much more that can be said about the effects.
 
BvU said:
Well, as I said, same result: same value, same direction.

Your reasoning for the induced emf is right, too. Since they don't tell us how the I2 comes about, there isn't much more that can be said about the effects.
Thanks for everything thus far. Apparently there's been an error with the question grading, so I'm pretty sure our answer we have come up to is the correct one. Thanks for everything.
 

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