MHB What is the formula for finding angle theta without accounting for height?

[xyz_1965]

Here is my set up.

Let t = theta for short

tan(t) = 324/550

arctan(tan t) = arctan(324/550)

t = arctan(324/550)

Correct thus far?

Note: What does "not to scale" mean in other words?

 

[skeeter]

$\tan{\theta} = \dfrac{324-1.6}{550}$

 

[xyz_1965]

$\tan{\theta} = \dfrac{324-1.6}{550}$

What is wrong with my approach?

 

[MarkFL]

What is wrong with my approach?

You aren't accounting for the height of the person.

 

[xyz_1965]

You aren't accounting for the height of the person.

Ok. I totally forgot about the height of the person.

tan (theta) = (height of tower - height of person)/(distance between person and the base of the tower). This will help me when I face a similar problem again.