What is the formula for finding the sum of an arithmatic series?

  • Thread starter Thread starter CathyLou
  • Start date Start date
  • Tags Tags
    Series
Click For Summary

Homework Help Overview

The discussion revolves around finding the formula for the sum of an arithmetic series, specifically focusing on the sum of the first n terms with a given first term and common difference. Participants explore the properties of arithmetic sequences and their applications in solving related problems.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the general term of an arithmetic sequence and express the sum in different forms. There are attempts to derive the sum formula and apply it to specific problems related to a novelist's writing schedule.

Discussion Status

Some participants have provided insights into the arithmetic series and its properties, while others are exploring specific applications and calculations. There is a mix of correct and incorrect reasoning, with some participants questioning assumptions and seeking clarification on their approaches.

Contextual Notes

Participants are working under the constraints of a homework assignment, which includes multiple parts to the problem. There is a focus on understanding the arithmetic series in the context of a practical scenario involving a novelist's writing plan.

CathyLou
Messages
173
Reaction score
1
I'd really appreciate it if someone could please help me with this question as I'm really stuck on it.

Prove that the sum of the first n terms of an arithmatic series with first term a and common difference d is given by

1/2[2a + (n-1) d]

Thank you.

Cathy
 
Physics news on Phys.org
Well, a start would be to write the expression for the general term of an arithmetic sequence: [tex]a_{i} = a_{1} + (i-1)d[/tex], where a1 is the first term, and d is the difference.
 
According to Wikipedia:

Express the arithmetic series in two different ways:

[tex]S_n=a_1+(a_1+d)+(a_1+2d)+ \dots +(a_1+(n-2)d)+(a_1+(n-1)d)[/tex]

[tex]S_n=(a_n-(n-1)d)+(a_n-(n-2)d)+ \dots +(a_n-2d)+(a_n-d)+a_n[/tex]

Add both sides of the two equations. All terms involving ''d'' cancel, and so we're left with:

[tex]2S_n=n(a_1+a_n)[/tex]

Rearranging and remembering that [tex]a_n = a_1 + (n-1)d[/tex], we get:

[tex]S_n=\frac{n( a_1 + a_n)}{2}=\frac{n[ 2a_1 + (n-1)d]}{2}[/tex]
 
Thanks so much to both of you for your help.

Cathy
 
I also stuck on the rest of the question. Could someone please help? I'd be really grateful for any assistance.

A novelist begins writing a new book. She plans to write 16 pages during the first week, 18 during the second and so on, with the number of pages increasing by 2 each week.

Find, according to her plan,

(b) how many pages she will write in the fifth week

(c) the total number of pages she will write in the first five weeks

(d) Using algebra, find how long it will take her to write the book if it has 250 pages.

Thank you.

Cathy
 
Well, if you understand what an arithmetic sequence is, then you should be able to solve the problem. Show us some work (if you get stuck), and we'll be glad to help. :smile:
 
radou said:
Well, if you understand what an arithmetic sequence is, then you should be able to solve the problem. Show us some work (if you get stuck), and we'll be glad to help. :smile:

Okay, an arithmatic series is a sequence where each term is found by adding a fixed number to the previous one.

For part b I got an answer of 24 pages and for part c I got an answer of 100 pages, but I still don't know how to do part d as I just got an answer of 235 weeks and that is obviously wrong.

Cathy
 
so you have 16, 18, 20. 22, 24, 26

so you can see each number increases by 2. and the first number starts as 16.

tn = 16 + (2n) - 2.

so:
250 = 16 + (2n) -2
234 = (2n) - 2
236 = 2n
n = 118 weeks

im pretty sure that's correct. hopefully someone will double check it. I am not good in math myself.

~Amy
 
physicsgal said:
so you have 16, 18, 20. 22, 24, 26

so you can see each number increases by 2. and the first number starts as 16.

tn = 16 + (2n) - 2.

so:
250 = 16 + (2n) -2
234 = (2n) - 2
236 = 2n
n = 118 weeks

im pretty sure that's correct. hopefully someone will double check it. I am not good in math myself.

~Amy

Thanks for your help!

Cathy
 
  • #10
physicsgal said:
so you have 16, 18, 20. 22, 24, 26

so you can see each number increases by 2. and the first number starts as 16.

tn = 16 + (2n) - 2.

so:
250 = 16 + (2n) -2
234 = (2n) - 2
236 = 2n
n = 118 weeks

im pretty sure that's correct. hopefully someone will double check it. I am not good in math myself.

~Amy

That isn't correct which should be obvious. After 5 week she will write 16 + 2(5) = 26 pages, so it can't take more than 10 weeks from then on.
 
  • #11
You're mixing the sum of the series with the members up. You have to solve [tex]250 = \sum_{i=1}^n a_{i} = \sum_{i=1}^n (16+(i-1)\cdot2)[/tex], where n is the number of weeks it takes to write 250 pages.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 22 ·
Replies
22
Views
3K