What Describes the Expansion of the Universe?

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SUMMARY

The Friedmann equation, represented as H² = (ḧ/a)² = (8πG/3)ρ - (kc²/a²), describes the expansion of the universe. It is derived from the 0-0 component of the Einstein field equations of General Relativity, utilizing the Friedmann-Robertson-Walker metric. Additionally, a Newtonian mechanics approach can also derive this equation, although it should not be considered a rigorous derivation. The equation incorporates parameters such as density (ρ), gravitational constant (G), and curvature (k), making it essential for understanding cosmological dynamics.

PREREQUISITES
  • Understanding of General Relativity and Einstein field equations
  • Familiarity with the Friedmann-Robertson-Walker metric
  • Basic knowledge of Newtonian mechanics and gravitational laws
  • Concept of cosmological density and its implications
NEXT STEPS
  • Study the derivation of the Friedmann equation using General Relativity
  • Explore the implications of the Friedmann equation on cosmic expansion
  • Learn about the role of dark energy in the universe's expansion
  • Investigate the relationship between curvature (k) and the universe's fate
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Astronomers, physicists, cosmologists, and students studying the dynamics of the universe and the principles of cosmology.

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Definition/Summary

The Friedmann equation is a dynamical equation that describes the expansion of the universe.

Equations

H^2 = \left( \frac{\dot{a}}{a}\right)^2 = \frac{8\pi G}{3} \rho - \frac{kc^2}{a^2}

Extended explanation

The Friedmann equation is derived from the 0-0 component of the Einstein field equations of General Relativity, on invoking the Friedmann Robertson Walker metric as the correct metric for the spacetime of the universe.

Note that, coincidentally, the equation can be derived by using Newtonian mechanics. We present this derivation here, with the caveat that it should not be taken as a rigorous derivation.

Consider a particle of mass m, a radius r from a uniform expanding medium of density ρ. The total mass of the material within the radius r is given by:

M = \frac{4\pi \rho r^3}{3}

Therefore the force from Newton's universal law of gravitation is given by:

F = -\frac{4\pi G\rho r m}{3}

And the gravitational potential energy of the particle is:

V= -\frac{4\pi G r^2 m}{3}

If we consider the energy conservation of the particle,

U= E_k + V

where E_k = \frac{1}{2} m \dot{r}^2

U must remain a constant and with r being written as comoving coordinates \mathbf{r} = a(t) \mathbf{x}

we have:

U = \frac{1}{2}m\dot{a}^2x^2 - \frac{4}{3} \pi G \rho a^2 x^2 m

Which gives the familiar:

H^2 = \left(\frac{\dot{a}}{a}\right)^2 = \frac{8\pi G}{3} \rho - \frac{kc^2}{a^2}

where we have defined kc^2 = -\frac{2U}{mx^2}

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