What is the Fundamental Frequency?

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SUMMARY

The fundamental frequency for a vibration with an overtone frequency of 990 Hz can be determined using the formula f_n = n*f_1, where f_1 represents the fundamental frequency. The overtone frequency f_2 is defined as f_2 = 2*f_1. By analyzing the options provided, the only valid fundamental frequency that satisfies the condition f_1 = 990/n for integer values of n is 330 Hz. Therefore, the correct answer is option A, 330 Hz.

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  • Understanding of fundamental frequency and overtone frequency concepts
  • Familiarity with the formula f_n = n*f_1
  • Basic knowledge of integer ratios in frequency analysis
  • Ability to manipulate algebraic equations
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Soaring Crane
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Which of the following could be the fundamental freq. for a vibration that has an overtone freq. of 990 Hz?

a. 330
b. 660
c. 148
d. 1980
e. 1990
(All in Hz.)

The formula that I think you have to use is f_n = n*f_1, where f_1 is fud. freq.

Then, I thought

f_2 = 2*f_1, where f_2 is the overtone freq. (is these a correct assumption?)

but 990/2 is 495.

Could someone direct me to the correct path of getting the solution?

I'm confused over the definitions of overtone and fund. freq.

Thanks.
 
Last edited:
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There's no reason to assume than n=2, so you just leave it as n.

So you have f_n = nf_1
Or f_1 = \frac {990}{n}

Which of the choices satisfies this condition for some integer n ?

Can you say if f_1 will be greater than or less than 990 Hz, from this ? Does this rule out any choices ?

The alternative is simply to notice that f_n/f_1 = n, so try the remaining choices of f_1 to see which one gives you an integer ratio.
 
Last edited:
Is the answer A?

The fud freq. would be less than 990, would it not? That leaves A and B, and 990/3 is 330.
 
That's right.
 

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