- #1
EroAlchemist
- 10
- 0
Homework Statement
An elastic cord vibrates with a frequency of 3.0 Hz with a mass of 0.60kg is hung from it. What is its frequency when only 0.38kg hangs from it?
Homework Equations
freq = (1/2Pi)*sqrt(k/m)
The Attempt at a Solution
freq = 3.0Hz = (1/2Pi)*sqrt(k/0.60kg)
= (4Pi^2)(9Hz)(.60kg) = k = 853.7 Nm
use k to calc freq:
freq = (1/2Pi)*sqrt(853.7Nm/0.38kg)
Freq = 7.54 Hz
Book gives correct answer as being 3.8 Hz. This seemed simple enough, but I'm obviously missing something. Thanks much for any help.