What is the gravitational potential energy of the obectj

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SUMMARY

The gravitational potential energy (GPE) of an object is calculated at its highest point using the formula E = 1/2mv^2. For a 0.7 kg object thrown vertically at 29 m/s, the GPE at the peak of its trajectory is equal to its initial kinetic energy. Additionally, for an 8.9 kg object with an initial speed of 21 m/s that gains 1.6 J of energy, the final speed after interaction can be determined by adjusting the kinetic energy for the energy gained and applying the kinetic energy formula.

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hi, please help me figure these problems out. much appreciated.

1. an object of mass .7kg is thrown vertically upwards at a speed of 29 m/s. What is the gravitational potential energy of the obect at the highest point of its trajectory?

2. an object of mass 8.9kg moves with initial speed 21 m/s then interacts with its environment, gaining 1.6J of energy. What is the speed of the object after after the interaction is completed?
 
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1. You have to consider the gravitational potential at the start point as zero. Then the potential at the highest point equals to the dynamic energy of the object or:

E = 1/2mv^2.

2. After the interaction, the dynamic energy is reduced by 1.6J. You can calculate the speed reduction via equ. deltaE=1/2m(deltav)^2. Then the final speed is known by a subtraction
 

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