What is the half-life and the error on the half-life?

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Homework Help Overview

The discussion revolves around determining the half-life of a beta emitter based on a measurement of counts over a day. The original poster seeks to understand both the calculation of the half-life and the associated error, particularly in the context of different measurement durations.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the mean lifetime and subsequently the half-life, raising questions about the calculation of error in the half-life. Some participants suggest looking into counting statistics for further insight.

Discussion Status

The discussion includes attempts to clarify the calculation process and error estimation. While one participant indicates they have resolved their question, others are still exploring the topic, particularly regarding the statistical aspects of the measurements.

Contextual Notes

Participants are discussing the implications of measurement duration on the half-life calculation and the associated uncertainties in their measurements.

stunner5000pt
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Homework Statement


You have a kilogram sample of a beta emitter and you want to establish its
half-life. You measure 100 counts over the period of a day. What is the half-life and
the error on the half-life? How would your answer be different if did a measurement
for the same material but only for one hour?


2. The attempt at a solution
To calculate the half life do i calculate the mean lifetime tau, first?

In that case \tau = 864 s/decay
i got this by dividing the number of counts 100/time in seconds for 1 day

we can calculate the half life now using t_{1/2} = \tau \ln 2

How would i calculate the error in th half life though?
Experimentally we could calculate it like this: the smallest unit of measurement of time we have is 1s so the error in the measurement of time is 0.5s. Also the error in the counting C was 0.5 counts/sec Then we can calculate the error in the lifetime as follows
\frac{\Delta \tau}{\tau} = \frac{\Delta C}{C} + \frac{\Delta t}{t}
which becomes
\Delta \tau = 436 s

But that is way too big isn't it? What have i done wrong? Please help!

Thank you for your help
 
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So can anyone offer any advice on this one?
 
https://www.physicsforums.com/showthread.php?t=94380
 
Look up counting statistics. I don't have any references on hand.
 
this question is fine thanks

i just figured it out

whats more important to me in any case is the particles in a tube thread
 

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