What is the initial acceleration of end B in a suspended rod system?

Click For Summary
SUMMARY

The initial acceleration of end B in a suspended rod system, where a rod of length 61.0 cm and mass 2.10 kg is supported by two strings, is determined after cutting the string on side B. Applying Newton's 2nd law for rotation, the acceleration can be calculated using the formula a = τ/I, where τ is the torque and I is the moment of inertia. The moment of inertia for the rod about its end is I = (1/3)ml², leading to a definitive calculation of the initial acceleration of end B once the string is severed.

PREREQUISITES
  • Understanding of Newton's 2nd law for rotation
  • Knowledge of torque and moment of inertia
  • Familiarity with basic physics concepts related to motion
  • Ability to perform calculations involving mass and length
NEXT STEPS
  • Review the principles of torque and its calculation in rotational systems
  • Study the moment of inertia for various shapes, focusing on rods
  • Explore real-world applications of Newton's laws in engineering
  • Practice problems involving suspended systems and forces
USEFUL FOR

Physics students, engineering students, and anyone interested in mechanics and dynamics of rigid bodies will benefit from this discussion.

chadgidge
Messages
1
Reaction score
0
A rod of length 61.0 cm and mass 2.10 kg is suspended by two strings which are 37.0 cm long, one at each end of the rod. The string on side B is cut. Find the magnitude of the initial acceleration of end B.
 
Physics news on Phys.org
What have you done so far? Where did you get stuck?

Hint: Review Newton's 2nd law for rotation.
 

Similar threads

  • · Replies 71 ·
3
Replies
71
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 7 ·
Replies
7
Views
10K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
1
Views
3K
Replies
7
Views
2K